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Nikolay [14]
3 years ago
9

There are 6 soccer teams in a recreational league. How many total games must be played in orders for all the teams to play each

other at least once?
6
9
12
15
Mathematics
1 answer:
crimeas [40]3 years ago
7 0
I believe the answer would be twelve
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What is the volume of this sphere with a radius of 9? options> (a)1024π m³ (b) 972π m³ (c)729π m³ (D)81π m³
svetlana [45]
\bf \textit{volume of a sphere}\\\\
V=\cfrac{4\pi r^3}{3}\quad 
\begin{cases}
r=radius\\
-----\\
r=9
\end{cases}\implies V=\cfrac{4\pi \cdot 9^3}{3}
6 0
3 years ago
Read 2 more answers
Question 20 (5 points)
laila [671]

9514 1404 393

Answer:

  B) ΔCAT is congruent to ΔDOG

Step-by-step explanation:

If angles are congruent, the triangles are <em>similar</em>. When both corresponding angles and corresponding sides are congruent, the triangles are <em>congruent</em>.

  ΔCAT is congruent to ΔDOG

7 0
3 years ago
Please help! I’ll do anything I’ll give u brainly!
lana66690 [7]

Answer:

y>0.5

Step-by-step explanation:

Rearrange the equation so "y" is on the left and everything else on the right.

Plot the "y=" line (make it a solid line for y≤ or y≥, and a dashed line for y< or y>

Shade above the line for a "greater than" (y> or y≥)

or below the line for a "less than" (y< or y≤).

y+x>1

-y      -y

x>1-y

2x+y<3

   -y    -y

2x<3-y

divide by 2

x<1.5-y/2

1.5-y/2>1-y

-1.5+y   -1.5+y

<u>y>0.5</u>

8 0
3 years ago
Please help! I really need help.
cupoosta [38]

Answer:

i believe it is a polynomial, but I need to see the options available to give you a better answer.

Step-by-step explanation:

trust lol

3 0
3 years ago
What two values of x are roots of the polynomial below
Anarel [89]
Both A and B will be answers to the solution. 

Since you already have the equation set and equal to 0, you can find the roots by first getting your a, b, and c values for the quadratic equation. 

a = 1 (number attached to the x^2)
b = -3 (number attached to the x)
c = 5 (number not attached to a variable)

Then we can use these values in the quadratic equation. 

\frac{-b +/-  \sqrt{ b^{2} -4ac } }{2a}

\frac{3 +/- \sqrt{ -3^{2} -4(1)(5) } }{2(1)}

\frac{3 +/- \sqrt{-11 } }{2}
6 0
3 years ago
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