The answer would be True.
Answer:
The code to this question can be given as:
Code:
int callsReceived,operatorsOnCall; //define variable as integer
Scanner ob= new Scanner(System.in);
//create object of scanner class for user input
System.out.println("Insert the value of callsReceived"); //print message.
callsReceived = ob.nextInt(); //input value.
System.out.println("Insert the value of operatorsOnCall"); //print message.
operatorsOnCall = ob.nextInt(); //input value.
if (operatorsOnCall == 0) //check number
{
System.out.println("INVALID"); //print message.
}
else
{
System.out.println(callsReceived/operatorsOnCall); //print value.
}
Explanation:
In the above code firstly we define 2 integer variable that name is already given in the question. Then we create the scanner class object for taking user input. Then we print the message for input first and second value from the user. then we use conditional statement. If the second variable that is operatorsOnCall is equal to 0. So It print INVALID. else it divide the value and print it.
Answer: True
Explanation:
TCP is the transmission control protocol which and TCP ACK is the transmission control handshake method which are used by TCP. It basically indicates the next sequence number in the method when the flag is set.
Firstly, the ACK (Acknowledge) send by the each end for the initial sequence number itself but it does not contained any type of data. In the TCP segment header ACK contain 32 bit field.
The acknowledgement is just a proof to clients that ACK is a specific to the SYN when the clients initiate.
Answer:
// program in C++.
#include <bits/stdc++.h>
using namespace std;
int main() {
// variable
int num;
cout<<"Enter the number between 20 and 98: ";
// read number
cin >> num;
while(num<20||num>98)
{
cout<<"Wrong input!!enter number between 20-98 only:";
cin>>num;
}
cout<<"The output is: ";
while(num % 10 != num /10)
{
// print numbers.
cout<<num<<" ";
// update num.
num--;
}
// display the number.
cout<<num<<endl;;
return 0;
}
Explanation:
Read a number from user and assign it to variable "num".Check if entered number is in between 20-98 or not.If input number is less than 20 or greater than 98 then ask again to enter a number between 20-98 until user enter a valid input.Then print the countdown from input number till both the digit of number are same.
Output:
Enter the number between 20 and 98: 99
Wrong input!!enter number between 20-98 only:12
Wrong input!!enter number between 20-98 only:93
The output is: 93 92 91 90 89 88
Enter the number between 20 and 98: 77
The output is: 77
