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kati45 [8]
3 years ago
5

A signal has a spectrum from 0 to 145 Hz, as shown below. It is sampled at a rate of 295 Hz. Find the region of the baseband spe

ctrum that will become corrupted and unrecoverable even if an ideal "brickwall" filter is used for recovery.
Please give answer with explaination. Its quiz que (Points : 5) None; all will be recoverable
15–145 Hz
90–145 Hz
135–145 Hz
Computers and Technology
2 answers:
kirza4 [7]3 years ago
7 0

Answer:  None; all will be recoverable

Explanation:

If a signal (band-limited) is sampled at regular intervals, it could be recoverable or not, based on the number of samples taken.

Let's assume that we want to take samples of a simple sinusoid; If we take more than two samples during a signal cycle, the original waveform will be able to be reconstructed, just passing the sampled waveform through a low-pass filter.

In the more general case in which the signal occupies a frequency spectrum, if the sample frequency is greater than the double of the highest frequency in the spectrum, the signal can be retrieved completely, according to the  Nyquist Theorem.

In this case , as the highest frequency is 145 Hz, it would be enough  to take samples at a rate greater than 290 Hz; As the sample rate is 295 Hz, all the signal can be recovered, at least, using an ideal "brickwall" low-pass filter.

djverab [1.8K]3 years ago
3 0

Answer:

95

Explanation:

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<h2>Answer:</h2>

    //======METHOD DECLARATION=========//          

    //method name: nicknames                                          

    //method return type: void                                            

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    public static void nicknames(String [] names){      

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       names = new String[] {"John", "Doe", "Brian", "Loveth", "Chris"};

       //using an enhanced for loop, print out the elements in the array

       for(String n: names){

           System.out.print(n + " ");

       }

       

    }

<h2>Explanation:</h2>

The program is written in Java. It contains comments explaining important parts of the code. Kindly go through these comments.

A few things to note.

i. Since the method does not return any value, its return type is <em>void</em>

ii. The method is made public so that it can be accessible anywhere in and out of the class the uses it.

iii. The method is made static since it will most probably be called in the static main method (at least for testing in this case)

iv. The method receives an array of type <em>String </em>as parameter since the names to be stored are of type <em>String</em>.

v. The format of initializing an array manually should follow as shown on line 7. The <em>new</em> keyword followed by the array type (String), followed by the square brackets ([]) are all important.

vi. An enhanced for loop (lines 9 - 11) is a shorthand way of writing a for loop. The format is as follows;

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=> followed by an opening parenthesis

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=> followed by a column

=> followed by the array

=> followed by the closing parenthesis.

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A complete code and sample output for testing purposes are shown as follows:

==================================================

public class Tester{

    //The main method

    public static void main(String []args){

       

       String [] names = new String[5];

       nicknames(names);

    }

   

  //The nicknames method

    public static void nicknames(String [] names){

       names = new String[] {"John", "Doe", "Brian", "Loveth", "Chris"};

       for(String n: names){

           System.out.print(n + " ");

       }

       

    }

}

==================================================

<h2>Output:</h2>

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<em>NB: To run this program, copy the complete code, paste in an IDE or editor and save as Tester.java</em>

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