We can solve this problem by referring to the standard
probability distribution tables for z.
We are required to find for the number of samples given the
proportion (P = 5% = 0.05) and confidence level of 95%. This would give a value
of z equivalent to:
z = 1.96
Since the problem states that it should be within the true
proportion then p = 0.5
Now we can find for the sample size using the formula:
n = (z^2) p q /E^2
where,
<span> p = 0.5</span>
q = 1 – p = 0.5
E = estimate of 5% = 0.05
Substituting:
n = (1.96^2) 0.5 * 0.5 / 0.05^2
n = 384.16
<span>Around 385students are required.</span>
Answer:
15 scores are less than 90
Step-by-step explanation:
Total 11 scores are less than 90 not 15
Answer:
1/40
Step-by-step explanation:
The answer to the question is boneless
Answer:
105 shifts
Step-by-step explanation:
Hourly net rate of pay = $12
1 shift = 8 hours
⇒ net pay per shift = $12 × 8 = $96
Total cost = tuition + residence + books
= $4500 + $4800 + $700
= $10,000
To calculate how many shifts Joanne needs to work, divide the total cost by the pay per shift and round it up:
Number of shifts = total cost ÷ net pay per shift
= $10,000 ÷ $96
= 104.1666666...
= 105 shifts
<u>Note</u>: we need to round up, as if Joanne works 104 shifts, she will earn $9,984 which is not quite enough to pay for tuition, residence and books.
