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3 years ago

Please simplify this equation

Mathematics

1 answer:

Citrus2011 [14]3 years ago

8 0

Use pemdas (parenthesis, exponents, multiply/divide, add/subtract);

5.9(4) + 4³ + 3.86

5.9(4) + 64 + 3.86

23.6 + 64 + 3.86

The answer is C) 91.46

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Determine g(x + a) − g(x) for the following function. g(x)=-5x^2-3x+2 g(x + a) − g(x)= ?

Sonja [21]

Easy
g(x+a)
sub x+a for every x in equation

g(x+a)=-5(x+a)^2-3(x+a)+2
g(x+a)=-5(x²+2xa+a²)-3x-3a+2
g(x+a)=-5x²-10xa-5a²-3x-3a+2
so now minus g(x)

g(x+a)-g(x)=
-5x²-10xa-5a²-3x-3a+2-(-5x²-3x+2)=
-5x²-10xa-5a²-3x-3a+2+5x²+3x-2=
-5x²+5x²-10xa-5a²-3x+3x-3a+2-2=
-10xa-5a²-3a

g(x+a)-g(x)=-5a²-10xa-3a

8 0

3 years ago

The mean of a population being sampled is 64, and the standard deviation is 6. If the sample size is 50, the standard error of t

alexira [117]

.........
.........
the answer is .85

6 0

3 years ago

PLEASE HELP HELP ME HELP ME HELP ME ITS MATH EZ STUFF

anyanavicka [17]

Answer:

Bruh your in high school yo know this stuff just make everything a decimal to get your answer. Lol you really forgot this?

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

The bus fare in a city is $2.00. People who use the bus have the option of purchasing a monthly coupon book for $28.00. With the

LekaFEV [45]

Answer:

56 = 56

Step-by-step explanation:

Given:

Bus fare = $2.00

coupon book = 28.00

bus fare w/ coupon book = $1.00

let x be the number of bus rides.

2.00x = 1.00x + 28.00

2.00x - 1.00x = 28.00

1x = 28.00

x = 28.00

24 bus rides for both to have the same cost.

2.00x = 1.00x + 28

2.00(28) = 1.00(28) + 28

56 = 28 + 28

56 = 56

4 0

3 years ago

Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,

sweet [91]

Answer:

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

$f'' = x - \frac{3}{2}$

$f' = \int {\left(x-\frac{3}{2}\right) } \, dx$

$f' = \int {x} \, dx -\frac{3}{2}\int \, dx$

$f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C$ , where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative ( $f'(4) = 1$ ):

$1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C$

$C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)$

$C = -1$

The first derivative is $y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1$ , and the particular solution is found by integrating one more time and using the initial condition ( $f(0) = 0$ ):