Solve the system of equations for the variables: 3x+y=7 2x-3y=1 (Hopefully it was easy enough because I'd like to give free poin
ts but I'm not allowed to ask really easy questions.)
2 answers:
Answer:
x = 2
y = 1
Step-by-step explanation:
3x + y = 7
2x - 3y = 1
Solve for y in the first equation.
y = 7 - 3x
Put y as 7 - 3y in the second equation and solve for x.
2x - 3(7 - 3y) = 1
2x - 21 + 9y = 1
11x - 21 = 1
11x = 1 + 21
11x = 22
x = 22/11
x = 2
Put x as 2 in the first equation and solve for y.
3(2) + y = 7
6 + y = 7
y = 7 - 6
y = 1
Answer:
x = 2, y = 1.
Step-by-step explanation:
3x + y = 7
2x - 3y = 1
Multiply the first equation by 3:
9x + 3y = 21 Add this to the second equation we get:
11x + 0 = 22
x = 2.
Substitute this value in the second equation:
2(2) - 3y = 1
-3y = -3
y = 1.
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Sense there's only a y, you'd assume y is 1 or 1y.
you'd make the 1 a negative 1 to get rid of the subtraction sign.
you'd add together the 2 ys making it 2y. then add -1 + 3, which would be 2.
so, the answer would be 2y + 2.
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