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Artyom0805 [142]
3 years ago
5

Solve the system of equations for the variables: 3x+y=7 2x-3y=1 (Hopefully it was easy enough because I'd like to give free poin

ts but I'm not allowed to ask really easy questions.)
Mathematics
2 answers:
jonny [76]3 years ago
8 0

Answer:

x = 2

y = 1

Step-by-step explanation:

3x + y = 7

2x - 3y = 1

Solve for y in the first equation.

y = 7 - 3x

Put y as 7 - 3y in the second equation and solve for x.

2x - 3(7 - 3y) = 1

2x - 21 + 9y = 1

11x - 21 = 1

11x = 1 + 21

11x = 22

x = 22/11

x = 2

Put x as 2 in the first equation and solve for y.

3(2) + y = 7

6 + y = 7

y = 7 - 6

y = 1

cluponka [151]3 years ago
4 0

Answer:

x = 2, y = 1.

Step-by-step explanation:

3x +  y = 7

2x - 3y = 1

Multiply the first equation by 3:

9x + 3y = 21   Add this to the second equation we get:

11x  + 0 = 22

x = 2.

Substitute this value in the second equation:

2(2) - 3y = 1

-3y =  -3

y = 1.

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<img src="https://tex.z-dn.net/?f=%28y%20-%201%29%28y%20%2B%203%29" id="TexFormula1" title="(y - 1)(y + 3)" alt="(y - 1)(y + 3)"
m_a_m_a [10]
Sense there's only a y, you'd assume y is 1 or 1y.

you'd make the 1 a negative 1 to get rid of the subtraction sign.

you'd add together the 2 ys making it 2y. then add -1 + 3, which would be 2.

so, the answer would be 2y + 2.
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