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MissTica
3 years ago
14

2) A month of the year is randomly selected.

Mathematics
2 answers:
sergeinik [125]3 years ago
6 0

Answer:

5/6

Step-by-step explanation:

First, list all the months of the year

January, February, March, April, June, July, August, September, October, November, December

There are 2 months that begin with the letter A : April and August

There are 12 months in the whole year

That leaves 10 (12-2) months that do not begin with the letter A

P(month that does not begin with A) = months that don't begin with A/ total

P(month that does not begin with A) = 10/12

The fraction can be reduced, since both the numerator and denominator can be divided by 2

P(month that does not begin with A) = (10/2) / (12/2)

P(month that does not begin with A) =5/6

lara31 [8.8K]3 years ago
3 0

Answer:

5/6

Step-by-step explanation:

The months of the year are: January February March April May June July August September October November December

There are 12 months

There are 10 months that do not start with A

P (month that does NOT begin with the letter A)

= number of months that do not start with A / total months

=10/12

 =5/6

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Answer:

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b) To solve this we are going to use the z score equation given as:

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8 0
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Answer:

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From Pythagoras theorem

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