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MissTica
3 years ago
14

2) A month of the year is randomly selected.

Mathematics
2 answers:
sergeinik [125]3 years ago
6 0

Answer:

5/6

Step-by-step explanation:

First, list all the months of the year

January, February, March, April, June, July, August, September, October, November, December

There are 2 months that begin with the letter A : April and August

There are 12 months in the whole year

That leaves 10 (12-2) months that do not begin with the letter A

P(month that does not begin with A) = months that don't begin with A/ total

P(month that does not begin with A) = 10/12

The fraction can be reduced, since both the numerator and denominator can be divided by 2

P(month that does not begin with A) = (10/2) / (12/2)

P(month that does not begin with A) =5/6

lara31 [8.8K]3 years ago
3 0

Answer:

5/6

Step-by-step explanation:

The months of the year are: January February March April May June July August September October November December

There are 12 months

There are 10 months that do not start with A

P (month that does NOT begin with the letter A)

= number of months that do not start with A / total months

=10/12

 =5/6

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Step-by-step explanation:

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2 years ago
3.1 Find the equation of the line passing through (4, 5) and parallel to the line 3x – 2y = 4.
valentinak56 [21]

                   \rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}

            <em>Find the equation of the line passing through (4, 5) and parallel to </em>

<em>                 3x-2y=4.</em>

<em />

<em>  </em>\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}

First of all, We need to convert this equation from standard form (ax+by=c) into slope-intercept form (y=mx+b).

\rightarrow First, add 2y on both sides:-

                            \Large\textsf{3x+2y=4}

\rightarrow Now, subtract 3x on both sides:-

                  \Large\textsf{2y=-3x+4}

\rightarrow Divide by 2 on both sides

    \Large\text{$y=-\displaystyle\frac{3}{2}x +2$}

\rule{300}{3}

Now, let's find the equation of the line that's parallel to the given line.

Remember, if lines are parallel to each other, then their slope's the same.

So the slope of the line that's parallel to the line whose equation we just found, is

\Large\text{$-\displaystyle\frac{3}{2}$}

Now let's write the equation in point-slope form:-

\hookrightarrow\sf{y-y_1=m(x-x_1)}

Replace numbers with letters, as follows:-

\sf{y-5=-\displaystyle\frac{3}{2} (x-4)}

The equation above is the equation in point-slope form.

Incase you need it converted to slope intercept form, refer to the steps below ~

Multiply -3/2 times x and -4:-

\hookrightarrow\sf{y-5=-\displaystyle\frac{3}{2} x-6}

Now, Add 5 on both sides:-

\hookrightarrow\sf{y=\displaystyle\frac{3}{2} x+1}

\Uparrow\sf{Our\:equation\:in\:slope\;intercept\;form}

<h3>Good luck with your studies.</h3>

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4 0
2 years ago
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Answer:

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<em>Hope this helps</em>

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3 0
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Answer:

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8 0
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