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poizon [28]
3 years ago
10

135.22 divided by 9 = ?

Mathematics
2 answers:
Serga [27]3 years ago
5 0

Answer:

15.0244444444

Step-by-step explanation:

135.22/ 9 = the answer

Hope it helps

Andrews [41]3 years ago
4 0

Answer: 15.0244444444

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Help me out please need help !!
BartSMP [9]
The answer is 1.25m + 3.50 = 12.35
7 0
2 years ago
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The formula for the surface of a cube is s 6s^2 where x is the length of one side. Find the length of the side of a cube with a
Advocard [28]
X=side length
6x^2 = surface area = 150
x^2 = 150/6=25
x=sqrt(25)=5
8 0
3 years ago
Can someone please help me!!!​
astra-53 [7]

Answer:

H. 260

Step-by-step explanation:

We'll begin this problem by first figuring out how many students will be able to sit at the first fourteen tables.

14 tables * 14 students = total students

196 = total students ( for those fourteen tables)

Now we also know that sixteen students can sit on the rest of the cafeteria tables.

We need to find the number of tables can hold sixteen students.

To do this, we'll lead with a simple equation:

18 tables total - 14 tables = # of remaining tables

4 = # of remaining tables

Now we're going to do the same thing we did with the original tables:

4 tables * 16 students = total students

64 = total students

Finally, we add both of the tables max values together:

64 + 196 = 260

7 0
2 years ago
The top one I need help with
brilliants [131]
Same thing as what you did on the bottom. Find numbers with both 7 as the base and numbers that add to 14 on the top. Possibilities:
1) 7^10•7^4
2)7^6•7^8
37^2•7^12
5 0
3 years ago
Find the inverse Laplace transform f(t) of the function F(s). Write uc for the Heaviside function that turns on at c, not uc(t).
zzz [600]

Answer:

F(t)=\frac{-1}{2}e^{7(t-7)}+\frac{1}{2}e^{-7(t-7)}

Step-by-step explanation:

We have given F(S)=\frac{7e^{-7s}}{s^2-49}

Now  F(S)=e^{-7s}G(s)

Here G(S)=\frac{7}{S^2-49}

Now first find the Laplace inverse of G(S)

Using partial fraction

\frac{7}{(s+7)(s-7)}=\frac{A}{(S+7)}+\frac{B}{S-7}

7=A(S-7)+B(S+7)

On comparing the coefficient

A=\frac{1}{2}  and B=\frac{-1}{2}  

On putting the value of A and B  

G(S)=\frac{-1}{2(S+7)}+\frac{1}{2(S+7)}

Taking inverse Laplace

G(t)=\frac{-1}{2}e^{7t}+\frac{1}{2}e^{-7t}

Now in G(s) there is onether term e^{-7s}

So F(t)=\frac{-1}{2}e^{7(t-7)}+\frac{1}{2}e^{-7(t-7)}

6 0
2 years ago
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