Question

-2e^8-8e^7 / 10e^2+40e

Answer 1

Answer:

  $\dfrac{-e^6}{5}$

Step-by-step explanation:

Maybe you want to simplify ...

  $\dfrac{-2e^8-8e^7}{10e^2+40e}=\dfrac{-2e^7(e+4)}{10e(e+4)}=\boxed{\dfrac{-e^6}{5}}$

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The distributive property and the rules of exponents are useful.

  ab +ac = a(b+c)

  (a^b)(a^c) = a^(b+c)

  1/a^b = a^-b