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4 years ago

-2e^8-8e^7 / 10e^2+40e

Mathematics

1 answer:

alukav5142 [94]4 years ago

4 0

Answer:

$\dfrac{-e^6}{5}$

Step-by-step explanation:

Maybe you want to simplify ...

$\dfrac{-2e^8-8e^7}{10e^2+40e}=\dfrac{-2e^7(e+4)}{10e(e+4)}=\boxed{\dfrac{-e^6}{5}}$

The distributive property and the rules of exponents are useful.

ab +ac = a(b+c)

(a^b)(a^c) = a^(b+c)

1/a^b = a^-b

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Please help I don't understand this and I was hoping someone could explain it to me please and thank you (:

patriot [66]

Answer:

I think it is asking you what quadrent they will be in but i aqm not sure.

Step-by-step explanation:

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3 years ago

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25% in it simplest form

oksano4ka [1.4K]

25% in it simplest form?

25%

25 ÷ 100 = 0.25

25/100

Simplify:-
GCF = 25

25 ÷ 25 = 1
100 ÷ 25 = 4
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25% = 0.25 = 25/100 = 1/4

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4 years ago

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Long division (4b^3+10b^2-32b+15) divided by (4b-6)

MrMuchimi

Answer:

4b^3 + 10b^2 - 32b + 15

___________________

2(2b - 3)

Step-by-step explanation:

Take out the greatest common factor of (4b - 6) which is 2 and 3.

8 0

3 years ago

Rita's company reimburses her expenses on food, lodging, and conveyance during business trips. The company pays $55 a day for fo

MArishka [77]

<span>"The company pays $55 a day for food and lodging and $0.45 for each mile traveled" means that if she travels m miles and is on a trip for x days then Rita will receive:

55x + 0.45m dollars.

Rita drove 300 miles, means that m=300. Thus </span>55x + 0.45m becomes <span>

</span> $55x+0.45m=55x+0.45 \cdot 300=55x+135$ (dollars.)

She was reimbursed $2,335 means that $55x+135=2,335$ .

Part A: $55x+135=2,335$ .

Part B:

We are given the equation 55x+135=2,335. Subtracting 135 from both sides we have:

55x=2,335-135=2,200.

Dividing both sides by 55, we get: x=2,200/55=40.

Part C: since x represents the number of days Rita spend on this trip, and x=40, then Rita spent 40 days on this trip.

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4 years ago

Consider writing onto a computer disk and then sending it through a certifier that counts the number of missing pulses. Suppose

Furkat [3]

Answer:

a) 0.164 = 16.4% probability that a disk has exactly one missing pulse

b) 0.017 = 1.7% probability that a disk has at least two missing pulses

c) 0.671 = 67.1% probability that neither contains a missing pulse

Step-by-step explanation:

To solve this question, we need to understand the Poisson distribution and the binomial distribution(for item c).

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

In which

x is the number of sucesses

$
e = 2.71828$ is the Euler number

$\mu$ is the mean in the given interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Poisson mean:

$\mu = 0.2$

a. What is the probability that a disk has exactly one missing pulse?

One disk, so Poisson.

This is P(X = 1).

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

0.164 = 16.4% probability that a disk has exactly one missing pulse

b. What is the probability that a disk has at least two missing pulses?

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

$P(X = 0) = \frac{e^{-0.2}*0.2^{0}}{(0)!} = 0.819$

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.819 + 0.164 = 0.983$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.983 = 0.017$

0.017 = 1.7% probability that a disk has at least two missing pulses

c. If two disks are independently selected, what is the probability that neither contains a missing pulse?

Two disks, so binomial with n = 2.

A disk has a 0.819 probability of containing no missing pulse, and a 1 - 0.819 = 0.181 probability of containing a missing pulse, so $p = 0.181$

We want to find P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.181)^{0}.(0.819)^{2} = 0.671$

0.671 = 67.1% probability that neither contains a missing pulse

8 0

3 years ago