Answer:
D^2 = (x^2 + y^2) + z^2
and taking derivative of each term with respect to t or time, therefore:
2*D*dD/dt = 2*x*dx/dt + 2*y*dy/dt + 0 (since z is constant)
divide by 2 on both sides,
D*dD/dt = x*dx/dt + y*dy/dt
Need to solve for D at t =0, x (at t = 0) = 10 km, y (at t = 0) = 15 km
at t =0,
D^2 = c^2 + z^2 = (x^2 + y^2) + z^2 = 10^2 + 15^2 + 2^2 = 100 + 225 + 4 = 329
D = sqrt(329)
Therefore solving for dD/dt, which is the distance rate between the car and plane at t = 0
dD/dt = (x*dx/dt + y*dy/dt)/D = (10*190 + 15*60)/sqrt(329) = (1900 + 900)/sqrt(329)
= 2800/sqrt(329) = 154.4 km/hr
154.4 km/hr
Step-by-step explanation:
Answer: 13 and 9
Step-by-step explanation:
because since there are two people 38-(8x2)=22
The only numbers that add up to 22 that have a difference of 4 are 13 and 9
Another way:
T=C+4
T+8+C+8=38
C+4+C+8=
$520
First, you multiply 26 by 4.
Then you multiply the product (104) by 5.
Find the function by taking the integral of the derivative.
F(x)=52x2−2x+C
Answer:
Scale factor for the drawing from actual park = 
Area of the actual park = 1200 cm²
Step-by-step explanation:
Length of the rectangular city park = 5 cm
Width of the rectangular park = 6 cm
Using scale factor 1 cm = 20 meters
Scale factor = 
Actual length = 5 × 20 = 100 meters
Actual width = 6 × 20 = 120 meters
Area of the rectangular park = length × width
= 100 × 120
= 1200 square meters
Therefore, Scale factor from actual length to the length in drawing = 1 : 20
Area of the rectangular park = 1200 square feet
