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Svetradugi [14.3K]
3 years ago
10

one night a theater sold 548 movie tickets. an adult’s costs $6.50 an child’s cost $3.50. in all, $2,881 was takin in. how many

of each kind of tickets were sold?
Mathematics
1 answer:
gavmur [86]3 years ago
3 0

Answer:

  • 321 adult tickets
  • 227 child tickets

Step-by-step explanation:

This sort of problem is easily solved by defining a variable to be the quantity of the higher-value contributor. Here, we can let x represent the number of adult tickets. Then total revenue is ...

  6.50x +3.50(548-x) = 2881

  3x +1918 = 2881 . . . . . . . . . . . . eliminate parentheses, collect terms

  3x = 963 . . . . . . . . . . . . . . . . . . subtract 1918

  x = 321 . . . . . . . . . . . . . . . . . . . . divide by 3

  548-x = 548 -321 = 227 . . . . . .number of child tickets

321 adult tickets and 227 child tickets were sold.

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Step-by-step explanation:

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find the domain of y equals 4 multiplied by the square root of the quantity 4 multiplied by x plus 2 end of quantity. a. x is gr
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2. Find the value of x.
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Answer:

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Step-by-step explanation:

3(x + 2) =24

Divide each side by 3

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4 0
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Solve by completing the square. <br> x2-6x+8 <br> Show solving steps please.
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Answer:

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Step-by-step explanation:

Let's factor x2−6x+8

x2−6x+8

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Factoring means we want something like

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Which numbers go in the blanks?

We need two numbers that...

Add together to get -6

Multiply together to get 8

Can you think of the two numbers?

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Fill in the blanks in

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