Question

C and D are mutually exclusive events. Find P(C or D). P(C)= 3/7= P(D)= 4/7 P(C or D)

Answer 1

Answer:

$P(C\ or\ D) = 1$

Step-by-step explanation:

Given

$P(C) = \frac{3}{7}$

$P(D) = \frac{4}{7}$

Required

$P(C\ or\ D)$

Since the events are mutually exclusive, then:

$P(C\ or\ D) = P(C) + P(D)$

So, we have:

$P(C\ or\ D) = \frac{3}{7} + \frac{4}{7}$

Take LCM

$P(C\ or\ D) = \frac{3+4}{7}$

$P(C\ or\ D) = \frac{7}{7}$

$P(C\ or\ D) = 1$