Answer:
C
Step-by-step explanation:
Multiples of 4: 4,8,16,20,24,28,32,36,40,44,48,52,56,60
Multiples of 15: 15,30,45,60
Th smallest number that they both can multiply to is 60
Answer: True
Solution:
Rearrange the equation to the LHS:
[x^2 + 8x + 16] · [x^2 – 8x + 16] - (x^2 – 16)^2 = 0
Factoring x^2+8x+16
x^2 - 4x - 4x - 16
= (x-4) • (x-4)
= = (x+4)2
So now we have an equation
(x + 4)^2 • (x - 4)^2 - (x^2 - 16)^2 = 0
Step 2: Evaluate the following:
(x+4)2 = x^2+8x+16
(x-4)2 = x^2-8x+16
(x^2-16)2 = x^4-32x^2+256
(x^2+8x+16) (x^2-8x+16 ) - (x^4-32x^2+256 )
0 = 0
Hence True
Given the sequence:
6, 10, 14, 18,...
We will find the 75th term
The given sequence is an arithmetic sequence
Because there is a constant common differnce
d = 18 - 14 = 14 - 10 = 10 - 6 = 4
The first term = a = 6
The general formula of the arithmetic sequence is as follows:

Where: n is the nth term
To find the 75th term, substitute with n = 75 and a = 6, d = 4

So, the answer will be the 75th term = 302
I think it’s A but I’m not sure
If f(x) = (6x-11), then f(-6) = -47.
We are provided in the question statement with a function "f(x)" whose output is a polynomial of 1 variable and degree 1.
To obtain the value of f(-6) from the output polynomial of the function f(x), we will simply need to substitute (-6) as the value of x in the polynomial and calculate the final value.
So,
![f(-6)=[(6*(-6))-11]\\or, f(-6)=(-36-11)\\or, f(-6)=-(36+11)\\or, f(-6) =-47](https://tex.z-dn.net/?f=f%28-6%29%3D%5B%286%2A%28-6%29%29-11%5D%5C%5Cor%2C%20f%28-6%29%3D%28-36-11%29%5C%5Cor%2C%20f%28-6%29%3D-%2836%2B11%29%5C%5Cor%2C%20f%28-6%29%20%3D-47)
Hence, f(-6) = -47.
- Polynomial: In mathematics, an expression of more than two algebraic terms, especially the sum of several terms that contain the same variable(s) of different powers and individual, distinct co-efficients.
- Function: In Mathematics, a function is an operator which on taking input, provides a certain output.
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