There are 600 students including the seventh and eighth graders at the party.
This problem uses the concept of percentages to define the conditions that are laid in front of us.
Let the original number of students be S , and the number of seventh graders be = 0.60S
We know that percent is used to convey the mathematical term of a fraction multiplied by 100.
Total students after 20 eighth graders arrive = S + 20
And we have that
Number of seventh graders / total number of students = 58%
.60S / [ S + 20 ] = .58 we multiply both sides by S + 20
0.60S =0 .58 [ S + 20]
.60S = .58S + 11.6 we subtract 0.58S from both the sides
0.02S = 11.6 we divide both the sides by .02
S = 11/6 / 0.02 = 580
So the total number of students = 580 + 20 = 600 .
Hence there are 600 students at the party at that time.
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M=230
m-80=150
add 80 to each sides
Answer:
119 student tickets and 95 non-student tickets
Step-by-step explanation:
I did a trial-and-error solution.
I started with 107 students and 107 non-students:
(107*$7)+(107*$12) = $2033
It was too high, which tells us that there should be more who paid for the cheaper price.
I ended up with 119 and 95:
(119*$7)+(95*$12) = $1973
Multiply the length and width for a rectangle like the one shown.
5.3(2.6) = 13.78 square yards.