The answer is A A number line with a closed circle on 3-
Answer: A. Women began to work outside the home
Step-by-step explanation:
The equation for a hyperbola is (x-h)/a - (y-k)/b = 1
Or (y-k)/a - (x-h)/b = 1
h represents the x value of the coordinate
k value represents the y value of the coordinate
together they represent a point, which is the center
So (h,k) is (x,y)
The asymptote is y-k = +/- b/a (x-h)
The transverse is the line that goes through the hyperbola.
[ Answer ]

[ Explanation ]
Rewrite 0.12 As A Fraction
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Rewrite Decimal As A Fraction With 1 As A Denominator
0.12 = 
Multiply To Remove Decimal Places
·
= 
Find GCF, Reduce Fraction
= 
0.12 = 
![\boxed{\boxed{[ \ Eclipsed \ ]}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cboxed%7B%5B%20%5C%20Eclipsed%20%5C%20%5D%7D%7D)
Answer:

Step-by-step explanation:
we have

we know that

substitute
