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igomit [66]
3 years ago
12

In how many ways can you select five people from a group of nine if the order of selection is important?

Mathematics
1 answer:
Anestetic [448]3 years ago
4 0
If the order of the selection is important we will apply the Arrangements formula A_{n} ^{k}= \frac{n!}{(n-k)!}.
In our case we will have A_{9}^{5}= \frac{9!}{4!} =5*6*7*8*9=15120.
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3 connecting lines are shown. Line D F is horizontal. Line D E is about half the length of line D F. Line F E is about one-third
mars1129 [50]

The inequality that explains why the three segments cannot be used to construct a triangle is ED + EF < DF

<h3>Inequalities </h3>

From the question, we are to determine which of the given inequalities explains why the three segments cannot be used to construct a triangle

From the given information,

Line DE is about half the length of line DF

That is,

ED = 1/2 DF

Also,

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Then, we can write that

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Learn more on Inequalities here: brainly.com/question/1447311

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5 0
2 years ago
Do you agree with the equation? Explain why or why not.
marin [14]
We have that

[√(2x+1)]+3=0
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therefore
the solution is not correct for x=4


[√(2x+1)]+3=0--------> [√(2x+1)]=-3---------> <span>There is no real solution for that equation
</span>Because (2x+1) >= 0
the solution is with complex numbers

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RSB [31]

Answer:

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