Question

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth. −2y2 + 6y = −2

Answer 1

-2y^2 + 6y + 2 = 0
a = -2, b = 6, c = 2
x = (- b + - sqrt(b^2-4ac))/(2a)
x=(-6+-sqrt(36-4*-2*2))/-4
x=(-6+-sqrt(36+16))/-4
x=(-6+-sqrt(52))/-4
x = (-6 +- 2sqrt13)/-4
x = (3 + - sqrt13)/2

Answer 2

Answer:

-0.3 Or 3.3

Step-by-step explanation:

-2y^2 + 6y + 2 = 0

X = -6 + 7.21/-4 or -7 - 7.21/-4

X = -0.3 or X = 3.3