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Mariana [72]
2 years ago
13

⚠️⚠️⚠️⚠️⚠️HELP HELP HELP HELP PLEASEEEE I

Mathematics
1 answer:
ser-zykov [4K]2 years ago
4 0

Answer:

im stuck on that too man

Step-by-step explanation:

You might be interested in
In a survey of 150 students at Kennedy Middle School, 48% said
BigorU [14]

Answer:

660 people

Step-by-step explanation:

48% people prefer thick pizza

1 375 people x 48% = 660

6 0
2 years ago
Map pours 3 2/3 cup of orange juice into measuring cup from a large container then he poured 1 1/4 cups back into the container
Alecsey [184]

Answer:

2 5/12 cups

Step-by-step explanation:

Map pours 3 2/3 cup of orange juice into measuring cup from a large container then he poured 1 1/4 cups back into the container

The amount of juice remaining in the measuring cup is calculated as:

3 2/3 - 1 1/4

= 3 - 1 + ( 2/3 - 1/4)

LCD = Lowest Common Denominator is 12

= 2 + (4 × 2 - 3 × 1/12)

= 2 + (8 - 3/12)

= 2 + 5/12

= 2 5/12 cups

Hence, the amount of juice remaining in the measuring cup = 2 5/12 cups of juice

7 0
3 years ago
Please help me. I need help please.
Mice21 [21]

Answer:

The correct options are;

EFGH has 4 congruent sides

Diagonal FH bisects angles EFG and EHG

Angle FEH is congruent to angle FGH

Step-by-step explanation:

1) Given that for a reflection, we have;

The distance of the reflected preimage from the line of reflection = The distance of the reflected image from the line of reflection

Therefore;

The distance of the point E from the line HF = The distance of the point G from the line HF

Also the reflection of an preimage (x, y) about the x-axis, gives an image (x, -y)

We can show that from the length of a line given by the equationl = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}, that the length EH ≅ GH and EF ≅ GF

Therefore since we are given that EH = EF, we have;

EH = GH = GF = EF by the definition of congruency, which gives 4 congruent sides

2) Given that EH = GH = GF = EF and HF = FH by reflective property, we have;

ΔEHF ≅ ΔGHF

∴ ∠GHF ≅ ∠EHF by Congruent Parts of Congruent Triangles are Congruent

Similarly, ∠GFH ≅ ∠EFH

Therefore, ∠GFH = ∠EFH and ∠GHF = ∠EHF

Therefore, diagonal FH bisects angles EFG and EHG

3) Given that ΔEHF ≅ ΔGHF, we have;

Angle FEH is congruent to angle FGH, by Congruent Parts of Congruent Triangles are Congruent

7 0
3 years ago
You and some friends are going to the fair. Small rides costs 4 tickets and while big rides costs 7 tickets. You and your friend
tensa zangetsu [6.8K]

Answer:

<em>4x+7y≤250</em>

Step-by-step explanation:

<u>Inequalities</u>

Let's call:

x = number of small rides

y = number of big rides

Since each small ride costs 4 tickets, x rides cost 4x tickets.

Since each big ride costs 7 tickets, y rides cost 7y tickets.

The total number of tickets is the sum of both:

Total tickets = 4x+7y

The friends have 250 tickets, so the total tickets of the rides cannot be greater than the 250 tickets available, thus:

4x+7y≤250

7 0
3 years ago
31
Hitman42 [59]

Answer:

L = 3(4) + 2(3) + 6

Step-by-step explanation:

.........

3 0
3 years ago
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