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lesya [120]
2 years ago
14

Find the radius and center of the circle given by the equation below. (x – 6)2 + (y + 4)2 = 7 r = 7 and center at (-6, 4) r = 7

and center at (6, -4) r = √7 and center at (-4, 6) r = √7 and (6, -4)
Mathematics
1 answer:
Blababa [14]2 years ago
3 0

Answer:

center at (6, -4) r = √7

Step-by-step explanation:

(x – 6)^2 + (y + 4)^2 = 7

This is in the form

(x – h)^2 + (y - k)^2 = r^2

Where (h,k) is the center of the circle and r is the radius of the circle

Rearranging the equation to match this form

(x – 6)^2 + (y -- 4)^2 = sqrt(7) ^2

The center is at (6, -4) and the radius is the sqrt(7)

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Let
x---------> <span>quantity (ton) of vegetables sold the first day
</span>y---------> quantity (ton)  of vegetables sold the second day
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x=y-3---------> equation 1
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using a graph tool
see the attached figure
the solution is
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the answer is
vegetables sold the first day----> 30 ton
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