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alexandr1967 [171]
3 years ago
6

Please help me I on 1-15 it’s past due ty!!❤️

Mathematics
2 answers:
erik [133]3 years ago
7 0
If you have snap you can use that just hold down on screen your problem
Oksana_A [137]3 years ago
4 0

Answer:

Problem 1 all you need to do is move the decimal place over four times as it says in your text book. Start out by making the decimal point visible by doing this 58,927. right there then move it over four times like this 5,892.7 one 589.27 two 58.927 three 5.8927 four. When they say move it over four places that's what it means. Now you should be able to do the rest on your own. GOOD LUCK!!!

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There are 88 marbles in a bin and 25 percent of the marbles are red how many red marbles are in the bin ?
alina1380 [7]

Answer:

22 marbles are red

25%=1/4

88÷4=22

#CarryOnLearning

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3 years ago
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What is the product?<br> (x2+3y+7) [yy+1)
DIA [1.3K]
2 x y2 + 2 x 3 y3 + 3y + 7 y2 + 7
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HELP PLS What is sin 62°?
Andreyy89

Answer:

15/17

Step-by-step explanation:

Remember SOH- CAH - TOA

7 0
3 years ago
Complete parts ​(a) through ​(c) below. ​(a) Determine the critical​ value(s) for a​ right-tailed test of a population mean at t
olga_2 [115]

Answer:

a) The critical value on this case would be t_{crit}=1.325

b) The critical value on this case would be t_{crit}=-1.345

c) The critical values on this case would be t_{crit}=\pm 2.201

Step-by-step explanation:

Part a

The system of hypothesis on this case would be:

Null hypothesis: \mu \leq \mu_0

Alternative hypothesis: \mu > \mu_0

Where \mu_0 is the value that we want to test.

In order to find the critical value we need to find first the degrees of freedom, on this case that is given df=20. Since its an upper tailed test we need to find a value a such that:

P(t_{20}>a) = 0.1

And we can use excel in order to find this value with this function: "=T.INV(0.9,20)". The 0.9 is because we have 0.9 of the area on the left tail and 0.1 on the right.

The critical value on this case would be t_{crit}=1.325

Part b

The system of hypothesis on this case would be:

Null hypothesis: \mu \geq \mu_0

Alternative hypothesis: \mu < \mu_0

Where \mu_0 is the value that we want to test.

In order to find the critical value we need to find first the degrees of freedom, given by:

df=n-1=15-1=14

Since its an lower tailed test we need to find b value a such that:

P(t_{14}

And we can use excel in order to find this value with this function: "=T.INV(0.1,14)". The 0.1 is because we have 0.1 of the area accumulated on the left of the distribution.

The critical value on this case would be t_{crit}=-1.345

Part c

The system of hypothesis on this case would be:

Null hypothesis: \mu = \mu_0

Alternative hypothesis: \mu \neq \mu_0

Where \mu_0 is the value that we want to test.

In order to find the critical value we need to find first the degrees of freedom, given by:

df=n-1=12-1=11

Since its a two tailed test we need to find c value a such that:

P(t_{11}>c) = 0.025 or P(t_{11}

And we can use excel in order to find this value with this function: "=T.INV(0.025,11)". The 0.025 is because we have 0.025 of the area on each tail.

The critical values on this case would be t_{crit}=\pm 2.201

5 0
4 years ago
A slice is made parallel to the base of a square pyramid.
strojnjashka [21]
The shape resulted is a square
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4 years ago
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