Let's see
![\sf [0.5\:0.5]\left[\begin{array}{cc}\sf b_1 &\sf r_1\\ \sf b_2&\sf r_2\end{array}\right]](https://tex.z-dn.net/?f=%5Csf%20%5B0.5%5C%3A0.5%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Csf%20b_1%20%26%5Csf%20r_1%5C%5C%20%5Csf%20b_2%26%5Csf%20r_2%5Cend%7Barray%7D%5Cright%5D)
r_1 and r2 are costs per pound
So
- It's r_1 is the cost of 1/2 pound rice at market one and r_2 is at market 2
Option J
So the question is "How many 1/4ths are inside 9 cups?"
We can divide 9 by 1/4:
9/1 ÷ 1/4.
Reciprocal and multiplication symbol:
9/1 * 4/1
36.
There are 36 one-fourth cups servings in 9 cups of peanuts.
3*3^2+2*10^2-15=212
The answer is 212
Answer:
2610/10730
2610/10730 = 0.24324324
0.24324324 X 100 = 24.324324
24%
Answer:
6.4331 × 10 5N
Step-by-step explanation:
Given the following :
Mass (m) of car = 1200kg
Initial Velocity (u) of car = 60 mph
Final velocity = 0 ( comes to rest)
Velocity in m/s = 60 / 2.24 = 26.785 m/s
Time (t) = 0.0500
Using the relation :
Ft = m(v - u)
Where,
v = final velocity ; u = initial velocity ; t = time ; F = force
F*0.05 = 1200(26.785 - 0)
0.05F = 32142.86 - 0
F = 32142.86 / 0.05
F = 642857.14 N
F = 6.43 × 10^5 N
