Answer:
in 13.95 years the senior class will have 100 students. 
Step-by-step explanation:
P(h) = p(0.92)^t (equation for exponential change)
P(h) - population of highschool (or senior class) = 100
p - staring amount = 320
t = time in years
100 = 320(0.92)^t
1/3.2 = .92^t (divide both sides by 320)
log(1/3.2, .92) = t (log base 0.92 of 1/3.2 equals t)
13.9497 = t
 
        
             
        
        
        
Given:


To find:
The value of  .
.
Solution:
We have,


Using properties of log, we get
 
      ![\left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Clog_a%5Cdfrac%7Bm%7D%7Bn%7D%3D%5Clog_am-%5Clog_an%5Cright%5D)
 
      
 
          ![[\log x^n=n\log x]](https://tex.z-dn.net/?f=%5B%5Clog%20x%5En%3Dn%5Clog%20x%5D)
Substitute  and
 and  .
.



Therefore, the value of  is
 is  .
.
 
        
             
        
        
        
Answer:
11
Step-by-step explanation:
x+y=8     y=3
x+3=8
-3     -3
x=11