Answer:
The cell interior would experience higher than normal Na+ concentrations and lower than normal K+ concentrations.
Explanation:
Na+/K+ ATPase exists in two forms: Its phosphorylated form has a high affinity for K+ and low affinity for Na+. ATP hydrolysis and phosphorylation of the Na+/K+ pump favor the release of Na+ outside the cell and binding of K+ ions from the outside of the cell. Dephosphorylation of the pump increases its affinity for Na+ and reduces that for K+ ions resulting in the release of K+ ions inside the cells and binding to the Na+ from the cells.
The presence of ATP analog would not allow the pump to obtain its phosphorylated form. Therefore, Na+ ions would not be released outside the cells. This would increase the Na+ concentration inside the cell above the normal. Similarly, the pump would not be able to pick the K+ from the outside of the cell resulting in reduced cellular K+ concentration below the normal range.
Set up the equation.
Since gravity and liquid densities are fixed (for the most part), the height of the liquid is the largest variable in the equation. The equation reads as Pfluid = ρgh, where ρ is the density of the liquid, g is the acceleration of gravity, and h is the height of the liquid (or depth of the fluid)
Your answer is Enamel it is the coating on teeth that helps prevent damage.
There are radio waves, microwaves and infrared waves
