Answer:
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
If AB is tangent to circle O at point A
then
AB is perpendicular to AO (radius) and Triangle ABO is a right triangle
so
----> by complementary angles in a right triangle
substitute the given value
area=
square =Side ×side
rectangle = length ×breadth
hope this help you
2/1
_1/3y=_1
y=_1+3/1
y=2/1
(b-1)²-9
= 4[(b - 1)(b - 1)] - 9
= 4[b² - b - b + 1] - 9
= 4(b² - 2b + 1) - 9
= 4b² - 8b + 4 - 9
= 4b² - 8b - 5
Hope this helps!