Answer:
Step-by-step explanation:
What is the cube root of 
? This is the question.
We can write:
![\sqrt[3]{27a^{12}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27a%5E%7B12%7D%7D)
We will use the below property to simplify:
![\sqrt[n]{a*b}=\sqrt[n]{a} \sqrt[n]{b}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%2Ab%7D%3D%5Csqrt%5Bn%5D%7Ba%7D%20%20%5Csqrt%5Bn%5D%7Bb%7D)
So, we have:
![\sqrt[3]{27a^{12}} =\sqrt[3]{27} \sqrt[3]{a^{12}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27a%5E%7B12%7D%7D%20%3D%5Csqrt%5B3%5D%7B27%7D%20%5Csqrt%5B3%5D%7Ba%5E%7B12%7D%7D)
We will now use below property to further simplify:
![\sqrt[n]{x} =x^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D%20%3Dx%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
Thus, we have:
![\sqrt[3]{27} \sqrt[3]{a^{12}} =3*(a^{12})^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D%20%5Csqrt%5B3%5D%7Ba%5E%7B12%7D%7D%20%3D3%2A%28a%5E%7B12%7D%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
We know power to the power rule: 
Now, we have:
This is the correct answer:
Answer:
C
Step-by-step explanation:
<u>Equation A</u>
16x - 7 = 11x - 32
(16x - 7) - 11x = (11x - 32) -11x
5x - 7 = -32
(5x - 7) + 7 = (-32) + 7
5x = -25
(5x)/5 = (-25)/5
x = -5
<u>Equation B</u>
-4x - 10 = 2x + 20
(-4x - 10) - 2x = (2x + 20) - 2x
-6x - 10 = 20
(-6x - 10) + 10 = (20) + 10
-6x = 30
(-6x)/-6 = (30)/-6
x = -5
Both Equation A and Equation B have a solution of -5.
Answer:
C
Step-by-step explanation:
Since all the graphs have the same line, you’re just looking for the correct shaded region. Since for both equations you want the shaded region to be less than the line, answer c solves the inequality.
Answer:
no
Step-by-step explanation:
since;
(4--3)/(4-1)≠(8-4)/(5-4)
Answer:
Step-by-step
A. C. C. 14. thats all i know, okay bye.
