Answer:
area of the rectangle =length *breadth
=14*5=70sq.ft
diameter =6ft
radius =3ft
area of the semi circle =1/2πr^2
=1/2*22/7*3*3=14.142sq.ft
area of the figure =area of the rectangle +area of the semi circle =70+14.142=84.142sq.ft
Answer:
for x = 14, the given ABCD is a RECTANGLE.
Step-by-step explanation:
Given : ABCD is a quadrilateral.
E is the intersection points of the diagonal AC and BD.
AE = x+10, and BE= 3x -18
Now, as we know:
IN A RECTANGLES , DIAGONALS BISECT EACH OTHER.
⇒ E is the mid point of AC and BD respectively.
⇒ AE = BE
⇒ x+10 = 3 x - 18
or, 10 + 18 = 3 x - x
or, 2 x = 28
or, x = 28/2 = 14 ⇒ x = 14
Hence, for x = 14, the given ABCD is a RECTANGLE.
Answer:
X =-3
Step-by-step explanation:
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