I think the answer is six
(1,1) , (2,2) , (3,3) , (4,4) , (5,5) , (6,6)
Palelogram area:
Knowing the base and the height, the area of the parallelogram is calculated by its formula:
A1 = b * h
Where
b: base
h: height.
We have then
b = root ((- 4 - (- 10)) ^ 2+ (2-2) ^ 2) = 6
h = root ((- 7 - (- 7)) ^ 2+ (3-2) ^ 2) = 1
A1 = (6) * (1) = 6 units ^ 2
Rectangle area
A2 = L * W
Where
L: long
W: Wide
We have then:
L = root ((1 - (- 2)) ^ 2 + (- 3 - (- 4)) ^ 2) = 3.16227766
W = root ((- 4 - (- 2)) ^ 2+ (2 - (- 4)) ^ 2) = 6.32455532
A2 = (3.16227766) * (6.32455532)
A2 = 20 units ^ 2
The total area is the sum of both ares:
A = A1 + A2
A = 6 + 20
A = 26 units ^ 2
Answer:
the area of this figure
A = 26 units ^ 2
Answer:
20 +/- $6.74
= ( $13.26, $26.74)
The 90% confidence interval for the difference in average amounts spent on textbooks (math majors - English majors) is ( $13.26, $26.74)
Step-by-step explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
x1-x2 +/- margin of error
x1-x2 +/- z(√(r1^2/n1 + r2^2/n2)
Given that;
Mean x1 = $200
x2 = $180
Standard deviation r1 = $22.50
r2 = $18.30
Number of samples n1 = 60
n2 = 40
Confidence interval = 90%
z(at 90% confidence) = 1.645
Substituting the values we have;
$200-$180 +/-1.645(√(22.5^2/60 +18.3^2/40)
$20 +/- 6.744449847374
$20 +/- $6.74
= ( $13.26, $26.74)
The 90% confidence interval for the difference in average amounts spent on textbooks (math majors - English majors) is ( $13.26, $26.74)
Answer:
v min (-2;-3)
Step-by-step explanation:
its going to be a parabola with a minimum of (-2;-3) I hope it helps
Answer:
The mean will reduce
Step-by-step explanation:
The total amount of money for the ten days divided by number of days will give mean 1, M₁
Removing the value for day seven will reduce the sum of money as it will be for 9 days only.In finding the mean, you will divide by 9 days to get mean M₂
Mean M₂ < M₁
