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loris [4]
3 years ago
14

When a number is decreased by 40% of itself the results is 54. What is the number

Mathematics
1 answer:
Orlov [11]3 years ago
5 0
Alright, this is simple. You know what the new number is, 54. You know the original number was decreased by 40%. Your looking for the original number, X. So set up an equation.
x-.4x=54
When X stands by itself, it's perceived to value 1.00
1.00-.4x=54
(1.00-.4 [40%]=.6)
.6x=54

Divide both sides by .6 to eliminate everything else.
.6x/.6=54/.6

You get 90. Your original number was indeed 90.
To check it, we can do 90/40%, or 90/.4=54

~Hope this helps!

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Answer:

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3 0
2 years ago
The difference between a number,x, and 4 is 9. find the number​
Elena-2011 [213]

let's set up an equation:

x-4=9

solve normally:

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6 0
3 years ago
Solve inequalities.
grigory [225]

Answer:

10. 7n - 1 < -8

Isolate the variable, n. Do the opposite of PEMDAS. Treat the < as equal sign, what you do to one side, you do to the other. First, add 1 to both sides:

7n - 1 (+1) < - 8 (+1)

7n < - 8 + 1

7n < - 7

Isolate the variable, n. Divide 7 from both sides:

(7n)/7 < (-7)/7

n < -7/7

n < -1

n < -1 is your answer.

11. 3 > -7v + 4v

Combine like terms, then isolate the variable, v. First, add -7v and 4v together.

3 > (-7v + 4v)

3 > (4v - 7v)

3 > (-3v)

Isolate the variable, v. Divide -3 from both sides. Note that since you are dividing a negative number, you must flip the sign:

(3)/-3 > (-3v)/-3

3/-3 > v

-1 < v

v > -1 is your answer.

~

4 0
3 years ago
Please help me on 7&amp;8 and please show your work :)
Llana [10]
7. 6/12 or 1/2 | 8. 5/12

5 0
3 years ago
Which of the following circles have their centers in the second quadrant? Check all that apply.
ivann1987 [24]
The given circles are given in standard form:
(x - xc)² + (y - yc)² = r²

The second quadrant is the one that has negative x coordinates and positive y coordinates.

This said, let's see all your options:
A) (x - 5)² + (y - 6)² = 25
xc = -(-5) = +5
yc = -(-6) = +6
C (5 , 6) is in the first quadrant.

B) (x + 1)² + (y - 7)² = 16
xc = -(+1) = -1
yc = -(-7) = +7
C (-1 , 7) is in the second quadrant.

C) (x - 4)² + (y + 3)² = 32
xc = -(-4) = +4
yc = -(+3) = -3
C (4, -3) is in the fourth quadrant.

<span> D) (x + 2)² + (y - 5)²= 9</span>
xc = -(+2) = -2
yc = -(-5) = +5
C (-2 , +5) is in the second quadrant.

Therefore, the correct answers are B and D.
7 0
3 years ago
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