Answer: A 24 cm piece of string is cut into two pieces , one piece is used to form a circle and the other piece is used to form a square.
How should this string be cut so that the sum of the areas is a minimum .
:
Let x = the circumference of the circle
then
(24-x) = the perimeter of the square
:
Find the area of the circle
find r
2*pi*r = x
r =
Find the area of the circle
A =
A =
A = sq/cm, the area of the circle
:
Find the area of the square
A = sq/cm the area of the square
The total area
At = +
Graph this equation, find the min
Min occurs when x=10.6 cm
cut string 10.6 cm from one end
Step-by-step explanation: Hope I help out alot (-: :-)
3s + 135 = 4.5s + 45
Now move the variables and coefficients
135 = 1.5s + 45
And then the numbers
90 = 1.5s
Simplify
90/1.5 = 1.5s/1.5
60 = s
Hope this helps!
Answer:
a+3
Step-by-step explanation:
You cannot go any further in answering this question. These two terms are not like terms so they cannot be combined. Therefore, the answer is just a+3 itself.
No 5/8 is bigger because half of 8 is 4 and 5 is greater than 4
Answer:
c = 10
Explanation:
Use Pythagoras theorem: a² + b² = c²
where 'a' and 'b' are legs and 'c' is the hypotenuse (the longest side)
Here given: a = 8 cm, b = 6 cm, c = ?
Substituting values:
8² + 6² = c²
c² = 64 + 36
c² = 100
c = √100
c = 10
