Answer:
(
4
x
+
3
)
(
3
x
−
2
)
Step-by-step explanation:
You should put 4 as x, -3 as y and a as slope to make an equation :

then you can find the slope and the correct equation of the line :
the slope is :

so the equation of the line will be

D is true
hope this helps
Answer:
The height of the hot air balloon is 1514.54 feet approximately.
Step-by-step explanation:
Consider the provided information.
The angle of elevation from the top of a 95-foot tall building to a hot air balloon in the sky is 76. If the horizontal distance between the building and the hot air balloon is 354 feet, find the height of the hot air balloon
The figure is shown below:
Let the height of the balloon is AD, the height of the building is BC.
Draw a line BE parallel to CD.
Therefore, AD=x+95, BC=95 and BE=CD=354 ft
Now in triangle
.




The height air balloon is 1419.54+95
=1514.54 ft
Hence, the height of the hot air balloon is 1514.54 feet approximately.
Answer:
1) $30,821 ( loan balance after 3 months in )
2) 8.56%
Step-by-step explanation:
Final Amount of compound interest: A = P ( 1 + i ) ^ n
p = principal = $30,000
r = interest rate = 11.41% = 0.1141
n = number of years
1) Loan balance after 3 months
n = 3/12 = 0.25 years
A = 30,000 ( 1 + 0.1141 ) ^ 0.25
= $30,821 ( loan balance after 3 months in )
2) Loan Balance after 1 year
A = 30,000 ( 1 + 0.1141 ) ^ 1
= $33423
interest on loan = 33423 - 30,000 = $3423
percentage of $40,000 is $3423
= 3423 / 40,000 * 100
= 8.56%
Answer:
9.56 ft/sec
Step-by-step explanation:
We are told that a 5.8-ft-tall person walks away from a 9-ft lamppost at a constant rate of 3.4 ft/sec.
I've attached an image showing triangle that depicts this;
Thus; dx/dt = 3.4 ft/sec
From the attached image and using principle of similar triangles, we can say that;
9/y = 5.8/(y - x)
9(y - x) = 5.8y
9y - 9x = 5.8y
9y - 5.8y = 9x
3.2y = 9x
y = 9x/3.2
dy/dx = 9/3.2
Now, to find how fast the tip of the shadow is moving away from the lamp post, it is;
dy/dt = dy/dx × dx/dt
dy/dt = (9/3.2) × 3.4
dy/dt = 9.5625 ft/s ≈ 9.56 ft/sec