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lukranit [14]
3 years ago
11

Evaluate the 6 trigonometric functions of theta for 540 degrees

Mathematics
1 answer:
Sophie [7]3 years ago
8 0
540 degrees is equivalent to 180 degrees. Cotangent and cosecant are invalid, sine, secant, tangent are all 0 and cosine is -1.
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Answer:

16)  18.5 hours

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tino4ka555 [31]
2 x 1/6 = 2/6 which can be reduced to 1/3
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problem 3 - 2 (whole number)
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sp2606 [1]

\displaystyle\\Answer:\ x=\sqrt{2}\ \ \ \ \ x=-\sqrt{2}\ \ \ \ \ x=\frac{ln5}{2}

Step-by-step explanation:

5x^2-x^2e^{2x}+2e^{2x}=10

Let:\ x^2=t  \ \ \ \ \ e^{2x}=v\\Hence,\\5t-tv+2v^2=10\\5t-tv+2v^2-10=10-10\\5t-tv-10+2v^2=0\\t(5-v)-2(5-v)=0\\(5-v)(t-2)=0\\5-v=0\\5-v+v=0+v\\5=v\\5=e^{2x}

<em>Prologarithmize both parts of the equation:</em>

ln5=lne^{2x}\\ln5=2x*lne\\ln5=2x*1\\ln5=2x\\

<u><em> Divide both parts of the equation by 2:</em></u>

\displaystyle\\x=\frac{ln5}{2}

t-2=0\\t-2+2=0+2\\t=2\\x^2=2\\x=\sqrt{2} \\x=-\sqrt{2}

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1 year ago
*** TIMED ***
Ymorist [56]
Answer is A.
c=139
b=18.04
a=11.76
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