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WITCHER [35]
4 years ago
8

When you are solving a system of equations by graphing, graph the lines and look for the point of __________________.

Mathematics
2 answers:
scoray [572]4 years ago
8 0
Intersection. I am pretty sure that is it.
solmaris [256]4 years ago
7 0
Intersection

Where the graph line matches with which column of graph...... take a line from that place to the axis to identify value on that point of intersection

Hope it helped !!
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12x-9=10x-15 Help me answer this please
zvonat [6]

Answer:

x = -3

Step-by-step explanation:

Given:

12x - 9 = 10x - 15

Now, let's add 15 to both sides of the equation.

12x + 6 = 10x

Now, let's subtract 12x from both sides of the equation.

6 = -2x

Now, let's divide both sides by -2.

-3 = x

3 0
3 years ago
Somebody pls help I have a math finals tomorrow it is 11:30 pm and I can't sleep because I am so nervous and worried
viktelen [127]

You'll do just fine, just make sure to study and have some sleep, okay?

5 0
3 years ago
Read 2 more answers
A trapezoid has sides of length 19 meters, 4.4 meters, 19 meters, and 17.2 meters. What is the perimeter?
Dafna11 [192]
19+19+4.4+17.2=59.6 is the perimeter
5 0
4 years ago
Find the equation of the straight line passing through the point (0,1) which is perpendicular to the line y= -2x + 2
mylen [45]

Answer:

y = 1/2x + 1

In order to evaluate a slope that is perpendicular to the given equation, you need to find the opposite reciprocal of the original slope. This means you take the original slope, flip the numerator and the denominator, and change the sign in front.

-2 ⇒ 1/2

Next, we need to substitute the information given into the point-slope formula.

The point-slope formula is:

y - y₁ = m(x - x₁)

y - 1 = 1/2(x - 0)

y - 1 = 1/2x

y = 1/2x + 1

Therefore, the line perpendicular to y = -2x + 2 is y = 1/2x + 1.

6 0
3 years ago
Rewrite each statement using the appropriate mathematical language 1. There exists a number b belonging to the set B 2. Even num
Shtirlitz [24]

Answer:

1. b ∈ B 2. ∀ a ∈ N; 2a ∈ Z 3. N ⊂ Z ⊂ Q ⊂ R 4. J ≤ J⁻¹ : J ∈ Z⁻

Step-by-step explanation:

1. Let b be the number and B be the set, so mathematically, it is written as

b ∈ B.

2. Let  a be an element of natural number N and 2a be an even number. Since 2a is in the set of integers Z, we write

∀ a ∈ N; 2a ∈ Z

3. Let N represent the set of natural numbers, Z represent the set of integers, Q represent the set of rational numbers, and R represent the set of rational numbers.

Since each set is a subset of the latter set, we write

N ⊂ Z ⊂ Q ⊂ R .

4. Let J be the negative integer which is an element if negative integers. Let the set of negative integers be represented by Z⁻. Since J is less than or equal to its inverse, we write

J ≤ J⁻¹ : J ∈ Z⁻

4 0
3 years ago
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