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miv72 [106K]
3 years ago
8

Given the midpoint and one endpoint of a line segment , find the other endpoint. Endpoint: (10, 12), midpoint: (6, 9)

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
3 0

The other end-point is: (2,6)

Step-by-step explanation:

Let the end-points be:

(x_1,y_1)\ and\ (x_2,y_2)

(x1,y1) = (10,12)

Mid-point = M = (6,9)

The formula for mid-point is given by:

M(x,y) = (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

Putting the values

(6,9) = (\frac{10+x_2}{2} , \frac{12+y_2}{2})

Putting respective coordinates equal

6 = \frac{10+x_2}{2}\\6*2 = 10+x_2\\12 = 10+x_2\\x_2 = 12-10\\x_2 = 2\\9 = \frac{12+y_2}{2}\\9*2 = 12+y_2\\18 = 12+y_2\\y_2 = 18-12\\y_2 = 6

The other end-point is: (2,6)

Keywords: Coordinate geometry, intercepts

Learn more about coordinate geometry at:

  • brainly.com/question/833559
  • brainly.com/question/8054589

#LearnwithBrainly

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anastassius [24]

Answer:

<h3>A. 50 yards.</h3>

Step-by-step explanation:

Given the coordinates of the length of PH as P(2,55)  and H(32, 15), to get the actual length of the land bridge from P to H, we will use the formula for calculating the distance between two points.

D = √(x₂-x₁)²+(y₂-y₁)²

PH = √(32-2)²+(15-55)²

PH = √(30)²+(-40)²

PH = √900+1600

PH = √2,500

PH = 50

Hence the actual length of the land bridge from P to H to the nearest yard is 50 yards.

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3 years ago
onyango wishes to fence a rectangular research plot using 100 m of wire .one end of the plot has a wall already erected .calcula
earnstyle [38]

Answer:

1250 m²

Step-by-step explanation:

Let x and y denote the sides of the rectangular research plot.

Thus, area is;

A = xy

Now, we are told that end of the plot already has an erected wall. This means we are left with 3 sides to work with.

Thus, if y is the erected wall, and we are using 100m wire for the remaining sides, it means;

2x + y = 100

Thus, y = 100 - 2x

Since A = xy

We have; A = x(100 - 2x)

A = 100x - 2x²

At maximum area, dA/dx = 0.thus;

dA/dx = 100 - 4x

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x = 100/4

x = 25

Let's confirm if it is maximum from d²A/dx²

d²A/dx² = -4. This is less than 0 and thus it's maximum.

Let's plug in 25 for x in the area equation;

A_max = 25(100 - 2(25))

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f(n) is the nth term

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The term just before nth term is f(n-1)

The term just before the (n-1)st term is f(n-2)

----------------

For example, let's say n = 3 indicating the 3rd term

n-1 = 3-1 = 2

n-2 = 3-2 = 1

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