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Tems11 [23]
1 year ago
11

A student sets up two reactions. Reaction 1 uses 0.180 mol/L of reactant, and Reaction 2 uses 0.510 mol/L of reactant. How many

times faster is Reaction 2 compared to Reaction 1?
Mathematics
1 answer:
il63 [147K]1 year ago
4 0

Given the data from the question, reaction 2 is 2.83 times faster compared to reaction 1

<h3>Data obtained from the question</h3>
  • Molarity of reaction 1 (R₁) = 0.180 mol/L
  • Molarity of reaction 2 (R₂) = 0.510 mol/L
  • Comparison =?

<h3>How to determine the comparison of reaction 2 to reaction 1</h3>

We can determine how many times faster is reaction 2 to reaction by doing the following:

R₂ / R₁ = 0.510 / 0.180

R₂ / R₁ = 2.83

Cross multiply

R₂ = 2.83 × R₁

From the above illustration, we can see that reaction 2 is 2.83 times faster than reaction 1

Learn more about Graham's law of diffusion:

brainly.com/question/14004529

#SPJ1

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Answer:

\hookrightarrow \sf  x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096

solving steps:

\rightarrow \sf (x + 4)^6

\bold{rewrite \ the \ following}

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\bold{basic \ addition \ of \ integers }

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\bold {final \ answer:}

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Step-by-step explanation:

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