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3 years ago

Write the fraction below as a sum or difference 5x+7 over 4

Mathematics

2 answers:

defon3 years ago

8 0

The answer is: 1.25x + 1.75

Black_prince [1.1K]3 years ago

7 0

$\frac{5x+7}{4} = \frac{5x}{4} + \frac{7}{4}$

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Is {(-5,1),(4,9),(6,10)} a function

sladkih [1.3K]

Yes it is a function!, all the first numbers are none repeating, for example it says -5,4,6 since they are not the same this is a function

7 0

3 years ago

PLEASE HELP WILL GIVE BRAINLIEST DO NUMBER 10

Licemer1 [7]

Answer:

Step-by-step explanation:

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Graphing the equation can be seen below

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2 years ago

Please Help<br><br> Solve x= 10+5/2

Vera_Pavlovna [14]

Answer:

Step-by-step explanation:

20/2 + 5/2 = 25/2 = 12 1/2

8 0

3 years ago

What is the x= in 2x-8<12<br> A.x<2<br> B.x<8<br> C.x<10<br> D.x<40

irinina [24]

The answer to your question is C. x<10

2x - 8 < 12
+8 +8
2x < 20
/2 /2

x < 10

Hope this helps! :)

7 0

3 years ago

What is the area of the scalene triangle shown (ABC), if AO = 10 cm, CO = 2 cm, BC = 5 cm, and AB = 12.20 cm? (Triangle AOB is a

lyudmila [28]

Answer:

The area of triangle ABC is $25\ cm^{2}$

Step-by-step explanation:

we know that

The area of triangle ABC is equal to the area of triangle ABO minus the area of triangle ACO

see the attached figure to better understand the problem

step 1

Find the area of triangle ABO

The area is equal to

$A=\frac{1}{2}(AO)(BO)$

substitute values

$A=\frac{1}{2}(10)(5+2)=35\ cm^{2}$

step 2

Find the area of triangle ACO

The area is equal to

$A=\frac{1}{2}(AO)(CO)$

substitute values

$A=\frac{1}{2}(10)(2)=10\ cm^{2}$

step 3

Find the area of triangle ABC

$35\ cm^{2}-10\ cm^{2}=25\ cm^{2}$

5 0

3 years ago