H = –16t2 + 156t + 105, when t = t', the time where the rocket hit the ground after it is launched, so 105= –16t'2 + 156t' + 105, so -16t'2 + 156t' = 0 implies t' =0 or -16t'+ 156= 0, equivalent to t'=9.75, so the answer is
b) <span>9.8 s</span>
Answer:
D. 25%
Step-by-step explanation:
There are two ways that I do this. Both of them are probably not what your teacher tells you, but hey, I got the right answer.
The first method is to go through the answers and do 14 x .10, 14 x .20, and so on until you get 3.50.
The second method is to do 14/3.5, which equals 4. This means 14 can be broken up into 3.50 four times. So, 3.50 is 1/4 of 14. What is 1/4 of 100%? 25%.
Log of 1 / 100 is - 2 because 10^( - 2 ) = 1 / 10^2 = 1 / 100 ;
Answer:
Step-by-step explanation:
I would say B
