Answer:
A. y=2x-9
B. 
Step-by-step explanation:
A. Parallel lines have the same slope. That means the line y=2x+3 has the same slope as any line parallel to it. So the slope is 2.
Using m=2, substitute it and (4,-1) into the point slope form and simplify to find the y-intercept.
B. Perpendicular lines have slopes which are negative reciprocals of each other. The slope of the line y=2x+3 is 2. The slope perpendicular to it is -1/2.
Using m=-1/2, substitute it and (4,-1) into the point slope form and simplify to find the y-intercept.
Hey, hope you're doing great today :)
Let's learn about what we need to learn to solve our equation.
We need to make this into a y=mx+b form.
That's the main thing you need to understand while doing this.
Now let's get onto the problem!
This is to much big of an equation to set up, so we need to change some things up.
We need to make one thing into a fraction.
It should look like y = -3/5x + 8.
This is in correct y = mx + b form.
Hopefully that clears things up :)
The answer is D i don’t know and i’m doing this for points but
answer ^^
step by step explanation
hope it helped !
and i don’t understand the equation
I believe that the answer is:
-1<2+y
I got -1 because if you do 2-3 you will get -1
And if not I am sorry.
:)
Answer:
42.5%
Step-by-step explanation:
First we have to complete the table. We know that there are forty part time students so sum(f)=n=40. So, for two courses frequency is 40-11-12=17.
The relative frequency is the proportion of respective frequency and the sum of frequency. So, the missing relative frequency for 1st course is 11/40=0.275.
The missing relative frequency can also be computed as by subtracting given relative frequencies from 1 as sum of relative frequencies is 1. So, 1-0.425-0.3=0.275.
The cumulative frequency of respective class is the sum of frequency of previous classes and frequency of respective class. The missing cumulative frequency is 11+17+12 or 28+12= 40.
So, the complete table is
# of Courses Frequency Relative Frequency Cumulative Frequency
1 11 0.275 11
2 17 0.425 28
3 12 0.3 40
The percent of students takes exactly two courses=0.425*100=42.5%
