Question

The balanced equation for the reaction of nitrogen gas and fluorine gas is

Answer 1

Answer:

We don't have a limiting reactant.

The reactants are present in stoichiometrically equivalent amounts.

Option D is correct

Explanation:

Step 1: Data given

Molecules N2 = 25 molecules

Molecules F2 = 75 molecules

Number of Avogadro = 6.02 * 10^23 / moles

Step 2: Calculate moles N2

Moles N2 = molecules N2 / number of Avogadro

Moles N2 = 25 / 6.02 * 10^23

Moles N2 = 4.15 * 10^-23 moles

Step 3: Calculate moles F2

Moles F2 = 75 molecules / 6.02 * 10^23

Moles F2 = 1.25 *10^-22 moles

Step 4: Calculate limiting reactant

For 1 mol N2 we need 3 moles F2 to produce 2 moles NF3

For 4.15 * 10^-23 moles N2 we need 1.25 * 10^-22 moles F2

OR  

For 25 molecules N2 we need 75 molecules F2

Both reactants will completely react.

This means we don't have a limiting reactant.

The reactants are present in stoichiometrically equivalent amounts.

Option D is correct