Answer:
1.70 g of NaNO₃
Explanation:
The balance chemical equation for given double displacement reaction is,
Pb(NO₃)₂ + 2 NaI → PbI₂ + 2 NaNO₃
Step 1: <u>Calculate moles of each reactant:</u>
Moles = Mass / M.Mass
For Pb(NO₃)₂:
Moles = 5.0 g / 331.21 g/mol
Moles = 0.0150 moles
For NaI:
Moles = 3.0 g / 149.89 g/mol
Moles = 0.020 moles
Step 2: <u>Calculate Limiting reagent as;</u>
According to equation,
1 mole of Pb(NO₃)₂ reacts with = 2 moles of NaI
So,
0.0150 moles of Pb(NO₃)₂ will react with = X moles of NaI
Solving for X,
X = 2 mol × 0.0150 mol / 1 mol
X = 0.030 moles of NaI
Hence, it means that NaI is the limiting reagent therefore, it will control the yield of Sodium Nitrate.
Step 3: <u>Find out moles of NaNO₃ formed:</u>
According to equation,
2 mole of NaI produced = 2 moles of NaNO₃
So,
0.020 moles of NaI will produce = X moles of NaNO₃
Solving for X,
X = 2 mol × 0.020 mol / 2 mol
X = 0.020 moles of NaNO₃
Step 4: <u>Calculate Mass of NaNO₃ produced;</u>
As, Moles = Mass / M.Mass
Or,
Mass = Moles × M.Mass
Putting values,
Mass = 0.020 mol × 84.99 g/mol
Mass = 1.70 g of NaNO₃
