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Sergeeva-Olga [200]
3 years ago
11

How many atoms are in 313.5 L of Bromine (Br) gas

Chemistry
2 answers:
pochemuha3 years ago
4 0

Answer:

The answer to the question is 79.91

horsena [70]3 years ago
3 0

Answer:

313.5 L of Br2 contains 8.428x10^24 atoms

Explanation:

Imol of Br2 occupies 22.4L

Therefore Xmol of Br2 will occupy 313.5L i.e

Xmol of Br2 = 313.5/22.4 = 14moles

1mole of Br2 contains 6.02x10^23 atoms.

Therefore 14moles of Br2 will contain = 14x6.02x10^23 = 8.428x10^24 atoms

Therefore 313.5 L of Br2 contains 8.428x10^24 atoms

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Maurinko [17]

Answer:

NaCl (Na is a metal and Cl is a nonmetal) MgO (Mg is a metal and O is a nonmetal) Al2O3, NaF, Na2O

Explanation:

You have to have a metal and a non metal together for it to be ionic

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3 years ago
The variable that a scientist observes to change while conducting an experiment is called the ___ variable.
Nimfa-mama [501]

Great Question!

The Answer Would Be "B" The "RESPONDING" Variable

4 0
3 years ago
Read 2 more answers
Osmotic pressure ____.a. occurs only in ionic solutions.b. is lower with 1 M NaCl than 1 M sucrose.c. is created using detergent
xenn [34]

Answer:

d. is the hydrostatic pressure produced on the surface of a semi-permeable membrane by osmosis.    

Explanation:

Osmosis -

It is the flow of the molecules of solvent from a region of higher concentration towards the region of lower concentration via a semipermeable membrane , is known as osmosis.

Osmotic pressure -

It refers to the minimum amount of pressure , which is required to be applied to the solution in order to avoid the flow of pure solvent via the semipermeable membrane , is referred to as osmotic pressure.

Or in simple terms ,

Osmotic pressure is the pressure applied to resists the process of osmosis.

Hence ,

From the given options in the question,

The correct option regarding osmotic pressure is d.

7 0
3 years ago
HELPP ASAP PLEASE SEE IMAGES
Simora [160]

Answer:

1st paragraph:

1.compound 2.physical 3.elements 4.water 5. gas 6.white 7. season 8.ratio 9.formula 10.elements 11.atoms 12.subscript 13.one

2nd paragraph

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Explanation:

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4 0
3 years ago
How would you make 5mls of a solution that is 2.0% lactose and 0.1M SPG buffer from separate stock solutions that are 6% lactose
Aliun [14]

Answer:

Check the explanation section.

Explanation:

The following steps should be followed orderly.

STEP ONE:

Use the dilution equation in the calculation of the volume for the stock solution. That is, C1 × V1 = C2 × V2.

Where C1 and C2 are the concentration of the stock solution and the diluted solution.

STEP TWO:

Put 6% of lactose and make sure to dilute it in order to make 2.0% lactose

and put it in Beaker A. Also, make sure to dilute the 1M to 0.1M SPG buffer in Beaker B.

STEP TWO:

Now, from beaker A containing 2% lactose, measure and remove 5.0 mL from it. Also, measure and remove 5.0 mL from beaker B containing 0.1M SPG.

So, in STEP TWO above we won't know how much water we need to use for dilution, thus, there is the need to make use of STEP ONE.

Therefore, from STEP ONE ABOVE, we have the dilution equation given as;

C1 × V1 = C2 × V2.

Hence, 6 × V1 = 2 × 5. Therefore, the volume needed from the stock solution, V1 = (2 × 5)/ 6 = 1.6 mL.

STEP THREE:

Now measure out 1.6 mL from the stock solution, that is 6% lactose and add it to 5mL of the diluted solution of 2% in beaker A into another container, say beaker C and add H2O to form SOLUTION X.

STEP FOUR:

Using the dilution equation again, Determine the the volume that is needed from 1M SPG.

C1 × V1 = C2 × V2.

V1 = ( 0.1 × 5)/ 1 = 0.5mL.

STEP FIVE:

measure 0.5mL out from the 1M SPG and 5 mL out of 0.1M SPG buffer and add water to it to form SOLUTION Y.

STEP SIX:

Now, mix solution X and solution Y together and take the required 5ml

7 0
3 years ago
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