3 years ago

What is the process of neutralization reactions?

1 answer:

6 0

ACID + BASE = SALT + WATER

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spin [16.1K]

Your experimental value would not be accurate

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3 years ago

Jlenok [28]

Answer:

sorry my phone died lol but here are the answers

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3 years ago

Colt1911 [192]

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3 years ago

max2010maxim [7]

Answer: A volume of 600 mL of 3.0 M $H_{2}SO_{4}$ solution can be prepared by using 100.0 mL OF 18 M $H_{2}SO_{4}$ .

Explanation:

Given: $V_{1}$ = ?, $M_{1} = 3.0 M\\$

$V_{2} = 100.0 mL$ , $M_{2} = 18 M$

Formula used to calculate the volume is as follows.

$M_{1}V_{1} = M_{2}V_{2}$

Substitute the values into above formula as follows.

$M_{1}V_{1} = M_{2}V_{2}\\3.0 M \times V_{1} = 18 M \times 100.0 mL\\V_{1} = \frac{18 M \times 100.0 mL}{3.0M}\\= 600 mL$

Thus, we can conclude that a volume of 600 mL of 3.0 M $H_{2}SO_{4}$ solution can be prepared by using 100.0 mL OF 18 M $H_{2}SO_{4}$ .

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3 years ago

puteri [66]

The sun i believe is one and wind

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3 years ago