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tresset_1 [31]
3 years ago
5

What is the molar concentration of [H3O+] in a cola that has a pH of 3.120?

Chemistry
1 answer:
ELEN [110]3 years ago
8 0

Answer:

  • [H₃O⁺] = 7.586×10⁻⁴ M

Explanation:

The <em>pH</em> of a solution is a measure of the <em>molar concentration of </em><em>H₃O⁺</em> ions in the solution.

The mathematical expresssion that states the relation between the molar concentration of H₃O⁺ ions and the pH of the solution is:

  • pH = - log [H₃O⁺].

This is pH is numerically equal to the negative decimal logarithm of the  molar concentration of H₃O⁺.

The square brackets are used to indicate molar concentration.

Thus:

  • pH = - log [H₃O⁺] ← equation
  • 3.120 = -log [H₃O⁺] ← substituting values
  • - 3.120 = log [H₃O⁺] ← product property of the multiplication
  • 10^{- 3.120}=[H_3O^+] ← antilogarithm property
  • [H₃O⁺] = 7.586×10⁻⁴ M ← result
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Ammonia reacts with sulfuric acid to produce the important fertilizer, ammonium hydrogen sulfate.
Liula [17]

Answer:

404.8g of (NH4)HSO4 is produced.

Explanation:

Step 1:

Data obtained from the question. This include the following:

Temperature (T) = 10°C = 10°C + 273 = 283K

Pressure (P) = 110KPa = 110/101.325 = 1.09atm

Volume (V) = 75L

Step 2:

Determination of the number of mole of ammonia, NH3.

The number of mole (n) of ammonia, NH3 can be obtained by using the ideal gas equation. This is illustrated below:

Note:

Gas constant (R) = 0.0821atm.L/Kmol

Number of mole (n) =?

PV = nRT

1.09 x 75 = n x 0.0821 x 283

Divide both side by 0.0821 x 283

n = (1.09 x 75) /(0.0821 x 283)

n = 3.52 moles

Step 3:

Determination of the number of mole ammonium hydrogen sulfate produced from the reaction.

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

NH3 + H2SO4 —> (NH4)HSO4

From the balanced equation above,

1 mole of NH3 produced 1 mole of (NH4)HSO4

Therefore, 3.52 moles of NH3 will also produce 3.52 moles of (NH4)HSO4.

Therefore, 3.52 moles of ammonium hydrogen sulfate, (NH4)HSO4 is produced.

Step 4:

Conversion of 3.52 moles of ammonium hydrogen sulfate, (NH4)HSO4 to grams. This is illustrated below:

Molar Mass of (NH4)HSO4 = 14 + (4x1) + 1 + 32 + (16x4) = 115g/mol

Number of mole of (NH4)HSO4 = 3.52 moles

Mass of (NH4)HSO4 =..?

Mass = mole x molar Mass

Mass of (NH4)HSO4 = 3.52 x 115 = 404.8g

Therefore, 404.8g of (NH4)HSO4 is produced.

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3 years ago
How many grams of Aspirin (acetylsalicylic acid) should we form in this reaction if we started with 2.08g of Salicyclic Acid?
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Taking into account the reaction stoichiometry, 2.713 grams of aspirin are formed when 2.08 grams of salicyclic acid reacts.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

C₄H₆O₃ + C₇H₆O₃ (Salicyclic Acid) →C₉H₈O₄ (aspirin) + C₂H₄O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • C₄H₆O₃: 1 mole
  • C₇H₆O₃: 1 mole
  • C₉H₈O₄: 1 mole
  • C₂H₄O₂: 1 mole

The molar mass of the compounds is:

  • C₄H₆O₃: 102 g/mole
  • C₇H₆O₃: 138 g/mole
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Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

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  • C₂H₄O₂: 1  mole ×60 g/mole= 60 grams

<h3>Mass of aspirin formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 138 grams of salicyclic acid form 180 grams of aspirin, 2.08 grams of salicyclic acid form how much mass of aspirin?

mass of aspirin=\frac{2.08 grams of salicyclic acidx 180 grams of aspirin}{138 grams of salicyclic acid}

<u><em>mass of aspirin= 2.713 grams</em></u>

Then, 2.713 grams of aspirin are formed when 2.08 grams of salicyclic acid reacts.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

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Under these specified non-standard conditions, the partial pressure of methanol is lower than its vapor pressure and this explains the reason for the spontaneous evaporation exhibited by methanol.

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