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iVinArrow [24]
3 years ago
14

Two numbers 6 away from -3 would it be 0?

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
5 0
Answer:9

Because,

Two number six’s is twelve.

And if you add twelve and negative three it would equal nine

Or subtract three from twelve
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3 years ago
Write an equation for line N
Annette [7]

Answer:

y=x-1

Step-by-step explanation:

6 0
3 years ago
Find a vector equation and parametric equations for the line through the point (7,4, 5) and parallel to the vector 3i 2j-k .
aleksley [76]

Answer: vector equation r = (7+3t)i + (4+2t)j + (5 - 5t)k

parametric equations: x = 7 + 3t; y = 4 + 2t; z = 5 - 5t

Step-by-step explanation: The vector equation is a line of the form:

r = r_{0} + t.v

where

r_{0} is the position vector;

v is the vector;

For point (7,4,5):

r_{0} = 7i + 4j + 5k

Then, the equation is:

r = 7i + 4j + 5k + t(3i + 2j - k)

<u><em>r = (7 + 3t)</em></u><u><em>i</em></u><u><em> + (4 + 2t)</em></u><u><em>j </em></u><u><em>+ (5 - 5t)</em></u><u><em>k</em></u>

The parametric equations of the line are of the form:

x = x_{0} + at

y = y_{0} + bt

z = z_{0} + ct

So, the parametric equations are:

<em><u>x = 7 + 3t</u></em>

<em><u>y = 4 + 2t</u></em>

<em><u>z = 5 - 5t</u></em>

4 0
3 years ago
What is the slope of the line passing through the points (0,-5) and (4,2)?
alukav5142 [94]

Answer:

\huge{ \boxed{ \tt{ \frac{ 7}{4} }}}

Step-by-step explanation:

\text{Let \: the \: points \: be \: A \: and \: B}

\sf{A \:( \: 0 \:,  - 5 \: )  \longrightarrow{ \: (x1 \:, y1)}}

\sf{B(4 \:, 2) \:  \longrightarrow{ \:( x2 \:, y2)}}

\underline{ \text{Finding \: the \: slope} }:

\boxed{ \sf{Slope =  \frac{y2 - y1}{x2 - x1}}}

\sf{➳ \: Slope =  \frac{2 - ( - 5)}{4  - 0}}

\sf{➳ \: Slope =  \frac{ 2 + 5}{4} }

\sf{➳ \: Slope =  \frac{7}{4} }

\text{Hope \: I \: helped!}

\text{Best \: regards!}

~\text{TheAnimeGirl}

3 0
4 years ago
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