Here it is given that AB || CD
< EIA = <GJB
Now
∠EIA ≅ ∠IKC and ∠GJB is ≅ ∠ JLD (Corresponding angles)
∠EIA ≅ ∠GJB then ∠IKC ≅ ∠ JLD (Substitution Property of Congruency)
∠IKL + ∠IKC 180° and ∠DLH + ∠JLD =180° (Linear Pair Theorem)
So
m∠IKL + m∠IKC = 180° ....(1)
But ∠IKC ≅ ∠JLD
m∠IKC = m∠JLD (SUBTRACTION PROPERTY OF CONGRUENCY)
So we have
m∠IKL + m∠JLD = 180°
∠IKL and ∠JLD are supplementary angles.
But ∠DLH and ∠JLD are supplementary angles.
∠IKL ≅ ∠DLH (CONGRUENT SUPPLEMENTS THEOREM)
Answer:
the answer is 10
Step-by-step explanation:
sorry it took so long i had to do something
9514 1404 393
Answer:
d. 76(cos(3π/16) +i·sin(3π/16))
Step-by-step explanation:
To form the product of 38cis(π/8) and 2cis(π/16), multiply the magnitudes and add the angles:
38cis(π/8) × 2cis(π/16) = (38×2)cis(π/8 +π/16) = 76cis(3π/16)
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In this context, a·cis(b) ≡ a(cos(b) +i·sin(b))
Answer:
Step-by-step explanation:
do u have to like determine if its true or not or solve the question?
