As a result of a transfer from one school to another, a boy has to walk one
1 answer:
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1) Substituting into point-slope form, the equation of the line is y-6=⅓(x-3), which rearranges to:
- y-6 = ⅓x - 1
- y = ⅓x + 5
So, we can now substitute in the coordinates of each of the options to see which point lies on the line.
- 3 = ⅓(6) + 5 -> 3 = 7, which is false.
- 6 = ⅓(7) + 5 -> 6 = 22/3, which is false.
- -3 = ⅓(-3) + 5 -> -3 = 4, which is false.
- 3 = ⅓(-6) + 5 -> 3 = 3, which is true.
So, the answer is (4) (-6, 3)
2) Substituting into point-slope form, the equation of the line is y - 5 = ¾(x-2), which rearranges to:
- y - 5 = 0.75x - 1.5
- y = 0.75x + 3.5
So, we can now substitute in the coordinates of each of the options to see which point lies on the line.
- 8 = 0.75(6)+3.5 -> 8 = 8, which is true.
- 9 = 0.75(5) + 3.5 -> 9 = 7.25, which is false.
- 1 = 0.75(-1) + 3.5 -> 1 = 2.75, which is false.
- 2 = 0.75(6) + 3.5 -> 2 = 8, which is false.
So, the answer is (1) (6, 8).
