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2 years ago

(2x2 + 5x - 7) + ( 3 - 4x2 + 6x)

Mathematics

1 answer:

velikii [3]2 years ago

3 0

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

Here's the solution :

$\qquad \sf \dashrightarrow \:(2 {x}^{2} + 5x - 7) + (3 - 4 {x}^{2} + 6x)$

$\qquad \sf \dashrightarrow \: 2{x}^{2} + 5x - 7 + 3 - 4 {x}^{2} + 6x$

$\qquad \sf \dashrightarrow \:2 {x}^{2} - 4 {x}^{2} + 5x + 6x - 7 + 3$

$\qquad \sf \dashrightarrow \: - 2 {x}^{2} + 11x - 4$

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2 years ago

Determine if there is a proportional relationship between the two quantities

Shalnov [3]

Answer:

The table a not represent a proportional relationship between the two quantities

The table b represent a proportional relationship between the two quantities

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $k=\frac{y}{x}$ or $y=kx$

Verify each table

Table a

Let

A ----> the independent variable or input value

B ----> the dependent variable or output value

the value of k will be

$k=\frac{B}{A}$

For A=35, B=92 ---> $k=\frac{92}{35}=2.63$

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the values of k are different

therefore

There is no proportional relationship between the two quantities

Table b

Let

C ----> the independent variable or input value

D ----> the dependent variable or output value

the value of k will be

$k=\frac{D}{C}$

For C=20, D=8 ---> $k=\frac{8}{20}=0.40$

For C=12.5, D=5 ---> $k=\frac{5}{12.5}=0.40$

the values of k are equal

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