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Blababa [14]
2 years ago
14

(2x2 + 5x - 7) + ( 3 - 4x2 + 6x)

Mathematics
1 answer:
velikii [3]2 years ago
3 0

\qquad\qquad\huge\underline{{\sf Answer}}♨

Here's the solution :

\qquad \sf  \dashrightarrow \:(2 {x}^{2}  + 5x - 7) + (3 - 4 {x}^{2}  + 6x)

\qquad \sf  \dashrightarrow \: 2{x}^{2}  + 5x   - 7 + 3 - 4 {x}^{2}  + 6x

\qquad \sf  \dashrightarrow \:2 {x}^{2}  - 4 {x}^{2}  + 5x + 6x - 7 + 3

\qquad \sf  \dashrightarrow \: - 2 {x}^{2}  + 11x - 4

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Answer:

Step-by-step explanation:

When we propose an hypothesis, it is either true or false. The same goes for a proposition.

The required objective here is to determine the truth value in the following proposition.

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(c) The sum of 3 and 4 is 12.

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From the first option:

(a) The integer 24 is prime.

The sentence is a proposition but the truth value is FALSE because a prime number is a number that can only be divide by 1 and itself but in the case of 24, Its factors include  1,2,3,4,6,8,12 and 24 which make 24 to falsify the proposition of being  a prime number.

(b) Is the integer 3​15​ even?

This option is not a proposition but rather a question since it has a question mark, however, 315 is an odd number since it is not divisible by 2.

( c)  The sum of 3 and 4 is 12.

This is a proposition and the truth value is FALSE

The sum of 3+4 = 7  ; Hence; 7 ≠ 12

(d)   -4 ∈ Ζ

This is a proposition and the truth value is TRUE.

-4 ∈ Ζ  is read as ( minus four is an integer  (∈)  of Z )

Yes, this is a proposition and its Truth value is TRUE , since  minus four is an integer  (∈)  of Z

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