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4 years ago

Help me with 9-10 plz help me asap!!!!!!!!

Mathematics

1 answer:

denpristay [2]4 years ago

5 0

You have to do it on your own because you need to show your work

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A gas is said to be compressed adiabatically if there is no gain or loss of heat. When such a gas is diatomic (has two atoms per

Tems11 [23]

Answer:

The pressure is changing at $\frac{dP}{dt}=3.68$

Step-by-step explanation:

Suppose we have two quantities, which are connected to each other and both changing with time. A related rate problem is a problem in which we know the rate of change of one of the quantities and want to find the rate of change of the other quantity.

We know that the volume is decreasing at the rate of $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ and we want to find at what rate is the pressure changing.

The equation that model this situation is

$PV^{1.4}=k$

Differentiate both sides with respect to time t.

$\frac{d}{dt}(PV^{1.4})= \frac{d}{dt}k\\$

The Product rule tells us how to differentiate expressions that are the product of two other, more basic, expressions:

$\frac{d}{{dx}}\left( {f\left( x \right)g\left( x \right)} \right) = f\left( x \right)\frac{d}{{dx}}g\left( x \right) + \frac{d}{{dx}}f\left( x \right)g\left( x \right)$

Apply this rule to our expression we get

$V^{1.4}\cdot \frac{dP}{dt}+1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}=0$

Solve for $\frac{dP}{dt}$

$V^{1.4}\cdot \frac{dP}{dt}=-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}\\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}}{V^{1.4}} \\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}$

when P = 23 kg/cm2, V = 35 cm3, and $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ this becomes

$\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}\\\\\frac{dP}{dt}=\frac{-1.4\cdot 23 \cdot -4}{35}}\\\\\frac{dP}{dt}=3.68$

The pressure is changing at $\frac{dP}{dt}=3.68$ .

7 0

4 years ago

What is the answer to (6+4)tothe3power-1tothe8power

Ipatiy [6.2K]

Hey there!

$\huge\boxed{(6 + 4)^3 - 1^8}$

$\huge\boxed{= 10^3 - 1^8}$

$\huge\boxed{10^3}$

$\huge\boxed{= 10\times10\times10}$

$\huge\boxed{= 100\times10 }$

$\huge\boxed{= 1,000}$

$\huge\boxed{1^{8}}$

$\huge\boxed{= 1\times1\times1 \times 1 \times 1 \times 1 \times 1 \times 1}$

$\huge\boxed{= 1 \times 1 \times 1 \times 1}$

$\huge\boxed{= 1\times1}$

$\huge\boxed{= 1}$

$\huge\boxed{1,000 - 1}$

$\huge\boxed{= 999}$

$\huge\text{Answer: \textsf{999}}$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

~ $\huge\boxed{\frak{Amphitrite1040:)}}$

8 0

3 years ago

You are given a fraction in simplest form. The numerator is not zero. When you write the fraction as a decimal, it is a repeatin

Agata [3.3K]

Hi there! The answer is 3, 6, 7, and 9.
1,2,4,5,8, and 10 cannot be put as denominators because if so, there would be:
1. no decimals
2. termination after one or two decimal places.

Cheers!
-10th Grader Snow

6 0

3 years ago

Solve 2x+y=3.5,-x+2y=2.5

padilas [110]

Answer:

y=1.7

x=.9

Step-by-step explanation:

3 0

3 years ago

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Is it possible for you guys to read a book called the giver and then write a whole essay, can you please do it it’s due tomorrow

STatiana [176]

Answer:

Step-by-step explanation:

We are not just going to do your writing essay for you. It's your fault you didn't get it done.

4 0

4 years ago