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3 years ago

7

Blueberries cost $4.00 per pound. How many pounds of blueberries can u buy for $1.00

2 answers:

Shkiper50 [21]3 years ago

8 0

Answer:

Step-by-step explanation:

Blueberries cost $4.00 for 1 pound. The number of blueberries that can be bought $1.00 = (1×1)/4 pounds

= 1/4 pounds

Anvisha [2.4K]3 years ago

5 0

One fourth of a pound
1/4 lb

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An airplane flies from City 1 at (0, 0) to City 2 at (33, 56) and then to City 3 at (23, 32). What is the total number of miles

uranmaximum [27]

Answer:

The airplane flies 95 miles.

Step-by-step explanation:

First we need to find the distance for the first segment using the formula for distance $D=\sqrt{(x_{2}-x_{1})^2 + (y_{2}-y_{1})^2}$ . Let's say $(x_{1},y_{1})$ is (0, 0) and $(x_{2},y_{2})$ is (33, 56). This gets us that the length of this segment is 65 miles.
Next, we need to find the distance for the second segment. Using the same formula for distance $D=\sqrt{(x_{2}-x_{1})^2 + (y_{2}-y_{1})^2}$ , we can say $(x_{1},y_{1})$ is now (33, 56) and $(x_{2},y_{2})$ is now (23, 32). This gets us that the length of this segment is 26 miles.
To get the total distance traveled, add the length of these two segments together (65 miles + 26 miles) to get 91 total miles traveled.

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2 years ago

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The directions for a calculation problem are to subtract 7 from 16 and then multiply by 4. Which expression shows this calcu

Nostrana [21]

Answer:

(16-7)x4

Step-by-step explanation:

You put 16-7 in parenthesis so it means to do it first, then multiply by 4.

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3 years ago

What is the range of (-1,7)(6,2)(0,4)(5,2)(-3,1)

Mrrafil [7]

Answer:

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3 years ago

Find the equation for the set of points whose distance from the y-axis equals the distance from the xz-plane.

julia-pushkina [17]

Answer:

$x_1^2 + z_1^2 = y_1^2$

Step-by-step explanation:

Let $p(x_1, y_1, z_1)$ be the point.

Any point on y-axis is (0, y, 0)

So, distance is

= $\sqrt{x_1^2+0 + z_1^2}$

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Now any point on x-z plane is $( x_1, 0, z_1 )$

Distance from p to this point is

= $\sqrt{0+y_1^2 + 0}$

= $\sqrt{y_1^2}$ .........(2)

Equating (1) and (2), we get

$\sqrt{x_1^2 + z_1^2} = \sqrt{y_1^2}$

$x_1^2 + z_1^2 = y_1^2$

This is the required equation.

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3 years ago

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tangare [24]

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Step-by-step explanation:

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