The directions for a calculation problem are to subtract 7 from 16 and then multiply by 4. Which expression shows this calcu

Mathematics

1 answer:

Nostrana [21]3 years ago

7 0

Answer:

(16-7)x4

Step-by-step explanation:

You put 16-7 in parenthesis so it means to do it first, then multiply by 4.

You might be interested in

A company is making building blocks. Each building block is a cube and has volume 125/729 ft cubed . How long is each side of th

MariettaO [177]

Answer: The length of each side of the building block is 0.56 feet

Step-by-step explanation:

A company is making building blocks. Each building block is a cube and has volume 125/729 ft cubed . Each of the building blocks has 6 faces which are squares, 8 vertices and 12 edges.

Since a square has all sides to be equal sides,

The volume of the cube = the volume of the building block =

Product of length,L, width, W and height, H.

Volume of the building block = L × W × H

Since length = width = height,

Volume of cube = L^3

From the information given,

Volume of a building block = 125/729ft cubed

L^3 = 125 / 729

Taking cube root of both sides of the equation,

L = cube root of 125/729

L = 5/9

= 0.56 feet

4 0

3 years ago

Joaquin is constructing the perpendicular bisector of ab. What should be his first step?

natali 33 [55]

Answer:

D. Open the compass so that the distance from the two points of the compass is wider than half the length of $\over{AB}$ .

Step-by-step explanation:

To construct a perpendicular for $\over{AB}$ , we must first take a compass & take the distance of its arms wider than half the length of $\over{AB}$ .

This is done in order to get two intersecting arcs in the top & bottom of $\over{AB}$ so that a perpendicular bisector can be drawn through it.

After two intersecting lines are drawn below & above $\over{AB}$ , draw a line joining these 2 points through their points of intersection. The point where it intersects $\over{AB}$ is the middle-most point of $\over{AB}$ & now a perpendicular bisector of $\over{AB}$ is constructed.

$\rule{150pt}{2pt}$