It is given that John wants to find the center of a wall so he can hang a picture. So, John measures the wall and <u>determines</u> it is 65.25 inches wide. Since John has determined that the wall measures a particular amount that means that John has <u>quantified</u> the width of the wall, which in this case comes out to be 65.25 inches.
Again, this is a single number. This means that the width of the wall is a <u>discrete</u> quantity.
Thus, 65.25 inches or 65.25" is a Quantitative and Discrete type of data. Thus, out of the given options, the first option is the correct one.
Answer:
This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:
"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"
Where X must be a positive number smaller than one, now we can solve it:
we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:
N = 45*(4/5) = 36
And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:
M = 36*X
now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")
M = 36*(1/2) = 18
So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.
Answer:
<h2>8(u + 3) = 8u + 24</h2>
Step-by-step explanation:
