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horsena [70]
3 years ago
11

Aster corporation accepted a $20,000, 9 percent 120-day note dated august 25 from lee company in settlement of a past bill. On O

ctober 25, Aster Corporation decided to discount the note at a discount of 8 percent. The proceeds to Aster Corporation are (blank)
Mathematics
1 answer:
serious [3.7K]3 years ago
6 0

Answer:

$20, 533.33

Step-by-step explanation:

From the question, we are given the following values

Principal = $20000

Rate = 8% = 0.08

Time( in years) = 120days = 4 months = 4/12 years = 1/3 years

Interest = Principal × Rate × Time

Interest = 20,000 × 0.08× (1/4)

Interest = $533.33

Hence, the proceeds to Aster Corporation are

$20000 + $533.33

= $20,533.33

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\frac{1}{4}

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4 0
3 years ago
"A study of the amount of time it takes a mechanic to rebuild the transmission for a 2005 Chevrolet Cavalier shows that the mean
Arada [10]

Answer:

85.31% probability that their mean rebuild time exceeds 8.1 hours.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 8.4, \sigma = 1.8, n = 40, s = \frac{1.8}{\sqrt{40}} = 0.2846

If 40 mechanics are randomly selected, find the probability that their mean rebuild time exceeds 8.1 hours.

This is 1 subtracted by the pvalue of Z when X = 8.1. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{8.1 - 8.4}{0.2846}

Z = -1.05

Z = -1.05 has a pvalue of 0.1469

1 - 0.1469 = 0.8531

85.31% probability that their mean rebuild time exceeds 8.1 hours.

4 0
3 years ago
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